Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz for SBI PO and LIC AAO Prelims 2019 on Mixed Word Problems.
Along with Reasoning, We will be providing good level Quantitative Aptitude Problems. Quantitative Aptitude needs a lot of practice and calculations. We have already given you an article on How to Score Maximum in Quantitative Aptitude. These Quantitative Aptitude quizzes will help you get past SBI PO Prelims and LIC AAO Prelims 2019.
Mixed Word Problems – 15 – Quantitative Aptitude Quiz 2019
The following Quantitative Aptitude Quiz has 12 questions from Mixed Word Problems with 10 minutes.
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The following questions are created as per the recent trends and level of SBI PO Prelims 2019.
Test Name: Mixed problem for SBI PO Prelims 2019
Duration: 10 min
Level: Moderate
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Question 1 of 12
1. Question
In an island of the Maldives, the natives have a peculiar process of determining their average earnings and expenditures. According to an old tradition, the average monthly earnings had to be calculated on the basis of 14 months in the calendar year, while the average monthly expenditure was to be calculated on the basis of 9 months in the year. This weird system of calculation always resulted in the natives underestimating their savings because there occurs an underestimation of their earning. The expenditure per month gets overestimated. Now keeping the above points in view try to answer the below questions:
Mr. Ghosh comes to his native island from Africa and makes his native community comprising of 173 families to calculate their average earning and the average expenditure on the basis of 12 months per the calendar year. The average estimated earning in his community according to the old system is 77 fasios per month. Assuming there are no other changes, what will be the percentage change in savings of the 173 families?
Correct
Solution:
Average Monthly earning (old system) = 77
So, Total Income of 173 families/14 = 77
So, Total Income of 173 families = 77×14
Now,Average Monthly earning of 173 families (new system) =
Total Income/12 = 77×14/12 = 89.83 fasios
But, we do not know the average monthly expenditure in either system.
Nor do we know the savings.
So, the required answer cannot be determined.Incorrect
Solution:
Average Monthly earning (old system) = 77
So, Total Income of 173 families/14 = 77
So, Total Income of 173 families = 77×14
Now,Average Monthly earning of 173 families (new system) =
Total Income/12 = 77×14/12 = 89.83 fasios
But, we do not know the average monthly expenditure in either system.
Nor do we know the savings.
So, the required answer cannot be determined. 
Question 2 of 12
2. Question
In an island of the Maldives, the natives have a peculiar process of determining their average earnings and expenditures. According to an old tradition, the average monthly earnings had to be calculated on the basis of 14 months in the calendar year, while the average monthly expenditure was to be calculated on the basis of 9 months in the year. This weird system of calculation always resulted in the natives underestimating their savings because there occurs an underestimation of their earning. The expenditure per month gets overestimated. Now keeping the above points in view try to answer the below questions:
In the previous question, the average estimated monthly expenditure is 21 fasios per month for the island. Determine the percentage change in the estimated savings of the 173 families.
Correct
Solution:
Average Monthly Income (old system) = 77
So, Total Income of 173 families/14 = 77
So, Total Income of 173 families = 77×14
Now, Average Monthly Income of 173 families (new system) =Total Income/12 = 77×14/12 = 89.83 fasios
Now, Average Monthly expenditure (old system) = 21
So Average Monthly Expenditure (new system) = 21×9/12 = 15.75Total Savings (old system) = 7721=56
Total Savings (new system) = 89.8315.75 = 74.08
%change = (74.0856)/56 x100 = 32.3%Incorrect
Solution:
Average Monthly Income (old system) = 77
So, Total Income of 173 families/14 = 77
So, Total Income of 173 families = 77×14
Now, Average Monthly Income of 173 families (new system) =Total Income/12 = 77×14/12 = 89.83 fasios
Now, Average Monthly expenditure (old system) = 21
So Average Monthly Expenditure (new system) = 21×9/12 = 15.75Total Savings (old system) = 7721=56
Total Savings (new system) = 89.8315.75 = 74.08
%change = (74.0856)/56 x100 = 32.3% 
Question 3 of 12
3. Question
Siddharth spends 30% of his income on his father’s medication, 20% on agricultural property and 10% on daughter’s education. The corresponding percentages for Akarsh are 40%. 25% and 13%. Given below are two conditions in 2 statements.
A.Siddharth spends more on agriculture than Akarsh.
B. Akarsh spends more on daughter’s education than Siddharth.We can determine who spends more on Father’s medication with the help of which of the above statements?
Correct
Solution:
Let Siddharth’s and Akarsh’s total income be 100x and 100y respectively.
So the amount spent by Siddharth on father, agriculture and daughter will be 30x, 20x and 10x respectively.
The corresponding amounts spent by Akarsh will be 40y, 25y and 13y.
We need to find relation between 30x and 40y i.e. we need the ratio 3x/4y
Now let us consider statement A alone:
We get 20x>25y
So 4x>5y i.e. x>1.25y
If we take x=1.3y, then 3x/4y=3.9x/4y<1
But if x=2y, then 3x/4y=6y/4y>1
So statement A alone is not sufficient.Consider statement B alone.
It says 13y>10x
So x<1.3y
For x=1.29y, 3x/4y = 3×1.29y/4y<1
Thus even for the highest value of x, we get 3x<4y.
For any value of x lesser than 1.29, 3x is surely going to be less than 4y.
So statement B is sufficient.Incorrect
Solution:
Let Siddharth’s and Akarsh’s total income be 100x and 100y respectively.
So the amount spent by Siddharth on father, agriculture and daughter will be 30x, 20x and 10x respectively.
The corresponding amounts spent by Akarsh will be 40y, 25y and 13y.
We need to find relation between 30x and 40y i.e. we need the ratio 3x/4y
Now let us consider statement A alone:
We get 20x>25y
So 4x>5y i.e. x>1.25y
If we take x=1.3y, then 3x/4y=3.9x/4y<1
But if x=2y, then 3x/4y=6y/4y>1
So statement A alone is not sufficient.Consider statement B alone.
It says 13y>10x
So x<1.3y
For x=1.29y, 3x/4y = 3×1.29y/4y<1
Thus even for the highest value of x, we get 3x<4y.
For any value of x lesser than 1.29, 3x is surely going to be less than 4y.
So statement B is sufficient. 
Question 4 of 12
4. Question
A pump can fill or empty an oil reservoir. The capacity of the oil reservoir is 3600m^{3}. The filling capacity of the pump connected to the reservoir is 10m^{3}/min less than its emptying capacity.If the pump takes 12 minutes extra to fill the reservoir than to empty it, determine the emptying capacity of the pump?
Correct
Solution:
Let x m^{3}/min be the filling capacity of the pump.
Therefore the emptying capacity=(x+10) m^{3}/min
The time taken to fill the reservoir=3600/x
Time taken to empty the reservoir=3600(x+10)
It takes 12 more minutes to fill the reservoir than to empty it
{3600/x } – {3600/(x+10) } =12
=>3600x+360003600x=12(x^{2}+10x)
=>36000=12(x^{2}+10x)
=>3000= x^{2}+10x
=> x^{2}+10x3000=0
=>x=60 or 50
Taking positive value of x=50
Emptying capacity =50+10=60 m^{3}/min
Incorrect
Solution:
Let x m^{3}/min be the filling capacity of the pump.
Therefore the emptying capacity=(x+10) m^{3}/min
The time taken to fill the reservoir=3600/x
Time taken to empty the reservoir=3600(x+10)
It takes 12 more minutes to fill the reservoir than to empty it
{3600/x } – {3600/(x+10) } =12
=>3600x+360003600x=12(x^{2}+10x)
=>36000=12(x^{2}+10x)
=>3000= x^{2}+10x
=> x^{2}+10x3000=0
=>x=60 or 50
Taking positive value of x=50
Emptying capacity =50+10=60 m^{3}/min

Question 5 of 12
5. Question
Ronnie starts driving from the market to the Star’s lab in his car. Meanwhile, Dr. Stein also drives from the market one hour after Ronnie and overtakes Ronnie after covering 30% of the distance from market to the lab. Both of them continue the drive even after the overtaking. On reaching Star’s lab, Dr. Stein reverses his car and meets Ronnie’s car, after covering 23 1/3 of the distance between Star’s lab and the market. In how much time did Dr. Stein cover the distance between market to the lab? ( in hours)
Correct
Solution:
Let the distance from market to Star’s lab be x
When Dr. Stein overtakes Ronnie for the first time, both of them cover= 3x/10
When Dr. Stein meets Ronnie after that, Dr. Stein covers (7x/10)+(7x/30) =28x/30
And Ronnie covers= (23x/30)(9x/30)=14x/30
Therefore, Dr. Stein is twice as fast as Ronnie.
Dr.Stein starts one hour after Ronnie and catches up in 1 hour.
Thus, Dr. Stein covers 0.3x (30 % of x) in one hour or x in 10/3 hr or 3 1/3 h.
Incorrect
Solution:
Let the distance from market to Star’s lab be x
When Dr. Stein overtakes Ronnie for the first time, both of them cover= 3x/10
When Dr. Stein meets Ronnie after that, Dr. Stein covers (7x/10)+(7x/30) =28x/30
And Ronnie covers= (23x/30)(9x/30)=14x/30
Therefore, Dr. Stein is twice as fast as Ronnie.
Dr.Stein starts one hour after Ronnie and catches up in 1 hour.
Thus, Dr. Stein covers 0.3x (30 % of x) in one hour or x in 10/3 hr or 3 1/3 h.

Question 6 of 12
6. Question
Tanmay spent less than ₹ 17500 to buy one quintal each of pomegranate, orange and guava. Which one of the following statements is sufficient ot determine which one of the three fruits bought was the costliest ?
A. 2 kg pomegranate and 1 kg guava cost less than 1 kg pomegranate and 2 kg guava.
B. 1 kg pomegranate and 2 kg orange together cost the same as 1 kg orange and 2 kg guava.
Correct
Solution: From A alone, 2P+G<1+2G=>P<G
We got no idea about olive, so it is not sufficient.
From B alone, P+2P=O+2G => P+N=2G
This also is not alone.
Using both, As P<G and P+O=2G=> G<O
Hence both are required.
Incorrect
Solution: From A alone, 2P+G<1+2G=>P<G
We got no idea about olive, so it is not sufficient.
From B alone, P+2P=O+2G => P+N=2G
This also is not alone.
Using both, As P<G and P+O=2G=> G<O
Hence both are required.

Question 7 of 12
7. Question
Nitu got an order for 480 khaddar blouses. She bought 12 charkhas and appointed some spinners to do it. However, many did not come on the working day. As a result, each of those who did come had to spin 32 more blouses than originally assigned with equal distribution of work. How many spinners had been appointed earlier and how many did not come?
Correct
Solution:
Solving by options,
Option a>
12 charkhas need to make 480 blouses.
Each charkha=40 blouses.
Due to the absence of few spinners, now each spinner had to make 40+32=72 blouses.
According to option, 12 are total spinners and 4 were absent hence 8 were spinning.
8 spinners made=8×72 >480 hence the option does not hold true.
Option c>
10 spinners did 480
One spinner did 48.
Remaining 6 spinners need to spin 48+32=130 blouse each
Tota 6 spinners will spin= 130x 6= 480 which satisfies the question
Hence answer is option C
Incorrect
Solution:
Solving by options,
Option a>
12 charkhas need to make 480 blouses.
Each charkha=40 blouses.
Due to the absence of few spinners, now each spinner had to make 40+32=72 blouses.
According to option, 12 are total spinners and 4 were absent hence 8 were spinning.
8 spinners made=8×72 >480 hence the option does not hold true.
Option c>
10 spinners did 480
One spinner did 48.
Remaining 6 spinners need to spin 48+32=130 blouse each
Tota 6 spinners will spin= 130x 6= 480 which satisfies the question
Hence answer is option C

Question 8 of 12
8. Question
Directions: Read the following information carefully and answer the questions.
A total of 3549237 athletes participated in an international marathon to be organized worldwide. The pie chart shows the distribution of athletes from different states. The table shows the ratio of athletes from rural and urban areas of the different places. It also shows the ratio of persons who live in pucca and kaccha houses in the rural areas. The information on the percentage of graduates and the persons with computer literacy from different places is also denoted in the table. Now keeping the data in view, solve the following questions.
City Rural : Urban Pucca : Kaccha % of Graduates % of Computer Literates Agra 7 : 6 3 : 7 31 67 Noida 3 : 2 13 : 6 79 89 Pune 5 : 11 7 : 19 13 21 Thane 19 : 21 9 : 4 49 39 Goa 9 : 13 11 : 19 23 37 Nagpur 13 : 17 21 : 4 56 24 Questions: Which place has the highest number of graduates?
Correct
Solution:
Agra=(3549237/360)x56x0.31=552104×0.31=171152
Noida=9859x129x0.79=1271811×0.79=1004730
Pune=9859x67x0.13=660553×0.13=85872
Thane=9859x29x0.49=28591×0.49=140097
Goa=9859x15x0.23=147885×0.23=34014
Noida has highest.
Incorrect
Solution:
Agra=(3549237/360)x56x0.31=552104×0.31=171152
Noida=9859x129x0.79=1271811×0.79=1004730
Pune=9859x67x0.13=660553×0.13=85872
Thane=9859x29x0.49=28591×0.49=140097
Goa=9859x15x0.23=147885×0.23=34014
Noida has highest.

Question 9 of 12
9. Question
Directions: Read the following information carefully and answer the questions.
A total of 3549237 athletes participated in an international marathon to be organized worldwide. The pie chart shows the distribution of athletes from different states. The table shows the ratio of athletes from rural and urban areas of the different places. It also shows the ratio of persons who live in pucca and kaccha houses in the rural areas. The information on the percentage of graduates and the persons with computer literacy from different places is also denoted in the table. Now keeping the data in view, solve the following questions.
City Rural : Urban Pucca : Kaccha % of Graduates % of Computer Literates Agra 7 : 6 3 : 7 31 67 Noida 3 : 2 13 : 6 79 89 Pune 5 : 11 7 : 19 13 21 Thane 19 : 21 9 : 4 49 39 Goa 9 : 13 11 : 19 23 37 Nagpur 13 : 17 21 : 4 56 24 Questions: Which place has the least number of computer literates for the following places?
Correct
Solution:
Agra=552104×0.67=369901
Noida=1271811×0.89=1131912
Pune=660553×0.21=138716
Goa=147885×0.37=54717
Goa has least computer literate
Incorrect
Solution:
Agra=552104×0.67=369901
Noida=1271811×0.89=1131912
Pune=660553×0.21=138716
Goa=147885×0.37=54717
Goa has least computer literate

Question 10 of 12
10. Question
Directions: Read the following information carefully and answer the questions.
A total of 3549237 athletes participated in an international marathon to be organized worldwide. The pie chart shows the distribution of athletes from different states. The table shows the ratio of athletes from rural and urban areas of the different places. It also shows the ratio of persons who live in pucca and kaccha houses in the rural areas. The information on the percentage of graduates and the persons with computer literacy from different places is also denoted in the table. Now keeping the data in view, solve the following questions.
City Rural : Urban Pucca : Kaccha % of Graduates % of Computer Literates Agra 7 : 6 3 : 7 31 67 Noida 3 : 2 13 : 6 79 89 Pune 5 : 11 7 : 19 13 21 Thane 19 : 21 9 : 4 49 39 Goa 9 : 13 11 : 19 23 37 Nagpur 13 : 17 21 : 4 56 24 Questions: The number of rural persons living in rural pucca houses of Nagpur is what percent more or less than the number of urban persons from Nagpur?
Correct
Solutions:
Nagpur pucca rural=9859×64 x(13/30)x(21/25)=630976 x(13/30)x(21/25)=259675
Nagpur urban=630976×17/30=357553
Answer=(357553259675)/357553 x100= 27.3 % less
Incorrect
Solutions:
Nagpur pucca rural=9859×64 x(13/30)x(21/25)=630976 x(13/30)x(21/25)=259675
Nagpur urban=630976×17/30=357553
Answer=(357553259675)/357553 x100= 27.3 % less

Question 11 of 12
11. Question
Directions: Read the following information carefully and answer the questions.
A total of 3549237 athletes participated in an international marathon to be organized worldwide. The pie chart shows the distribution of athletes from different states. The table shows the ratio of athletes from rural and urban areas of the different places. It also shows the ratio of persons who live in pucca and kaccha houses in the rural areas. The information on the percentage of graduates and the persons with computer literacy from different places is also denoted in the table. Now keeping the data in view, solve the following questions.
City Rural : Urban Pucca : Kaccha % of Graduates % of Computer Literates Agra 7 : 6 3 : 7 31 67 Noida 3 : 2 13 : 6 79 89 Pune 5 : 11 7 : 19 13 21 Thane 19 : 21 9 : 4 49 39 Goa 9 : 13 11 : 19 23 37 Nagpur 13 : 17 21 : 4 56 24 Questions: If 17% of graduates from Pune shift to Thane, what is the new number of graduates in Thane?
Correct
Solution:
Graduates shifting from Pune= 85872×0.17=14598
New number of graduates in Thane=140097+14598=154695
Incorrect
Solution:
Graduates shifting from Pune= 85872×0.17=14598
New number of graduates in Thane=140097+14598=154695

Question 12 of 12
12. Question
Directions: Read the following information carefully and answer the questions.
A total of 3549237 athletes participated in an international marathon to be organized worldwide. The pie chart shows the distribution of athletes from different states. The table shows the ratio of athletes from rural and urban areas of the different places. It also shows the ratio of persons who live in pucca and kaccha houses in the rural areas. The information on the percentage of graduates and the persons with computer literacy from different places is also denoted in the table. Now keeping the data in view, solve the following questions.
City Rural : Urban Pucca : Kaccha % of Graduates % of Computer Literates Agra 7 : 6 3 : 7 31 67 Noida 3 : 2 13 : 6 79 89 Pune 5 : 11 7 : 19 13 21 Thane 19 : 21 9 : 4 49 39 Goa 9 : 13 11 : 19 23 37 Nagpur 13 : 17 21 : 4 56 24 Questions: If another place Chennai has 37.7% less computer literates than Noida. Find the number of computer literates in Chennai.
Correct
Solution:
Number of computer literates in Noida=1131912
10037.7=62.3%
Hence Number of computer literates in Chennai= 1131912×0.623=705181
Incorrect
Solution:
Number of computer literates in Noida=1131912
10037.7=62.3%
Hence Number of computer literates in Chennai= 1131912×0.623=705181
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