Hello and welcome to exampundit. Here is a set of Reasoning Quiz for IBPS Clerk Prelims 2018 on Inequalities. The following reasoning quiz has 11 questions from Inequalities with 10 minutes. [WpProQuiz 218]  

Reasoning Quiz - Inequalities - IBPS Clerk Prelims 2018 - 1

Directions (Qs.1-5): In the following questions, the symbols @, #, $, * and % are used as illustrated below: ‘P @ Q’ means ‘P is not smaller than Q’. ‘P # Q’ means ‘P is neither greater than nor equal to Q’. ‘P $ Q’ means ‘P is neither smaller than nor greater than Q’. ‘P * Q’ means ‘P is not greater than Q’. ‘P % Q’ means ‘P is neither smaller than nor equal to Q’. Now, in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true? Give answer (a) if only Conclusion I is true. (b) if only Conclusion II is true. (c) if either Conclusion I or II is true. (d) if neither Conclusion I nor II is true. (e) if both Conclusions I and II are true.  
  1. Statements:
M $ K, D * K, R # K Conclusions: (I) D $ M (II) M % D [su_spoiler title="Show Solution"] (c) M = K .…. (i); D ≤ K ….. (ii); R < K ..… (iii) From (i) and (ii), we get M = K ≥ D –> M ≥ D Hence, either M > D (conclusion II) or M = D(conclusion I) is true[/su_spoiler]    
  1. Statements:
F * M, M % R, E @ F Conclusions: (I) M % E (II) R @ E [su_spoiler title="Show Solution"] (d) F ≤ M… (i); M > R… (ii); E ≥ F… (iii) From (i) and (iii), no specific relation can be obtained between M and E. Similarly, no specific relation can be obtained between R and E.[/su_spoiler]  
  1. Statements:
H $ K, T # H, W * T Conclusions: (I) K % W (II) T # K [su_spoiler title="Show Solution"] (e) H = K… (i); T < H…(ii), W≤T …(iii) From (i), (ii) and (iii), we get K = H > T ≥ W –> K > W (conclusion I) and T < K (conclusion II).[/su_spoiler]  
  1. Statements:
N % A, A # L, F $ N Conclusions: (I) L % F (II) F % A [su_spoiler title="Show Solution"] (b) N > A… (i), A < L… (ii), F = N…(iii) From (i) and (iii), we get F = N > A–> F > A (conclusion II). But no specific relation can be obtained between L and F. Hence, conclusion I is not necessarily true.[/su_spoiler]  
  1. Statements:
B * D, D $ M, F % M Conclusions: (I) B # M (II) F % B [su_spoiler title="Show Solution"] (b) B < D…(i); D = M…(ii); F > M …(iii) From (i), (ii) and (iii), we get F > M = D > B –> B < M and F > B (conclusion II). Since, B < M, therefore, conclusion I is not necessarily true. [/su_spoiler]   Directions (Qs. 6-11): In the following questions the symbols +, ×, ?, @ and $ are used with the following meanings: P + Q means P is neither smaller nor greater than Q. P × Q’means P is neither equal to nor smaller than Q. P ? Q means P is neither greater than nor equal to Q. P @ Q means P is either greater than or equal to Q. P $ Q means P is not equal to Q. Now, in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true. Give answer (a) if only conclusion I is true; (b) if only conclusion II is true; (c) if either I or II is true: (d) if neither I nor II is true; and (e) if both I and II are true.  
  1. Statement:
P $ Q, Q × R, P + R Conclusions: (I) Q × P (II) P ? Q [su_spoiler title="Show Solution"] (e) P ≠ Q ...(i), Q > R ... (ii), P = R ...(iii) From (ii) and (iii), we get Q > R = P --> Q > P. Hence, Both I and II are true. [/su_spoiler]    
  1. Statement:
A + B, B $ C, C ? A Conclusions: (I) C $ A (II) B + C [su_spoiler title="Show Solution"] (a) A = B ... (i), B≤ C ... (ii), C < A ... (iii) From (iii), conclusion I is true. II contradicts statement (ii), hence, it is not true.[/su_spoiler]    
  1. Statement:
Y @ Z, Z × Q, Q $ P Conclusions: (I) Y ? Q (II) Y ? P [su_spoiler title="Show Solution"] (d) Y≥ Z ...(i), Z > Q ... (ii), Q ÷ P ...(iii) From (i) and (ii), we get Y > Z > Q --> Y > Q ... (A) Hence, I is not true. From (iii), two possible relationships between P and Q are; Case I: When P > Q Now, using (A), we get Y > Q < P --> no conclusion. Case II: When Q > P using (A), we get Y > Q > P --> Y > P. Hence, II is not true.[/su_spoiler]    
  1. Statement:
E × F, F @ L, L+ N Conclusions: (I) N + F (II) E × L [su_spoiler title="Show Solution"] (b) E > F .... (i), F > L ... (ii), L = N ...(iii) From (ii) and (iii), we get F≥ L= N --> F≥ N or N′ F. Hence, I may be true but not necessarily so. From (i) and (ii), we get E > F > L --> E > L Hence, II is true.[/su_spoiler]    
  1. Statement:
H @ J. J ? K, K × M Conclusions: (I) H @ M (II) M × J [su_spoiler title="Show Solution"] (d) H ≥ J ... (i), J < K ... (ii), K > M ... (iii) From (ii) and (iii), we get J < K > M fi no relationship between J and M can be established. Hence, II can’t be established. Again, combining all we can’t conclude Thee relationship between H and M. Hence, I is not true.[/su_spoiler]    
  1. Statement:
M @ T, T + V, V ? E Conclusions: (I) V + M (II) V ? M [su_spoiler title="Show Solution"] (c) M ≥ T ... (i), T = V .... (ii), V < E ...(iii) From (i) and (ii), we get M ≥ T = Vfi M ≥ V --> ei-->er V = M or V < M is true.[/su_spoiler]  

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