Hello and welcome to exampundit. Here is a set of Reasoning Quiz on Coded Inequalities for Bank and Insurance exam.
Directions (Qs. 1 - 5): In the following questions, the symbols @, ©, ★, $ and # are used with the following meaning:
‘P @ Q’ means ‘P is neither smaller than nor equal to Q’.
‘P © Q’ means ‘P is not smaller than Q’.
‘P★Q’ means ‘P is not greater than Q’.
‘P $ Q’ means ‘P is neither smaller than nor greater than Q’.
‘P # Q’ means ‘P is neither greater than nor equal to Q’.
Now, in each of the following questions, assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true? Give answer
(a) if only conclusion I is true.
(b) if only conclusion II is true.
(c) if either conclusion I or II is true.
(d) if neither conclusion I nor II is true.
(e) if both conclusions I and II are true.
- Statements:
Z # N, F © N, F ★ K
Conclusion :
(I) K $ N
(II) K @ Z
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Option: B
Explanation:
Z < N ....(i); F ≥ N .... (ii); F ≤ K ....(iii) Combining all, we get
K ≥ F ≥ N > Z
→ K = N and K > Z
Hence, conclusion I (K = N) is not necessarily true but conclusion II (K > Z) is true.
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- Statements:
D $ T, T © M, M # K
Conclusion:
(I) M $ D
(II) D @ M
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Option: C
Explanation:
D = T ....(i); T ≥ M ....(ii); M < K ... (iii) Combining (i) and (ii), we get
D = T ≥ M
→ D ≥ M
→ D = M or D > M
Hence, either conclusion I (M = D) or conclusion II (D > M) is true.
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- Statements:
W © A, B ★ A, B @ M
Conclusions:
(I) B # W
(II) W $ B
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Option: C
Explanation:
W ≥ A ...(i); B ≤ A .... (ii); B > M ... (iii) Combining all, we get
W ≥ A ≥ B > M
→ B ≤ W
→ B < W or B = W
Hence, either conclusion I or II is true.
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- Statements:
J ★ M, M $ N, N # T
Conclusions:
(I) T @ J
(II) T $ J
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Option: A
Explanation:
J ≤ M ....(i); M = N ...(ii); N < T .... (iii)
Combining all, we get
J ≤ M = N < T
→ T > J
Hence, only conclusion I is true
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- Statements:
V ★ F, F @ R, R © G
Conclusions:
(I) G # V
(II) G @ V
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Option: D
Explanation:
V ≤ F .... (i); F > R .... (ii); R ≥ G ....(iii)
Combining (ii) and (iii), we get F > R ≥ G ....(iv)
Comparing (i) and (iv), we can’t get any specific relationship between G and V. Hence, both conclusions are not true.
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Directions (Qs. 6-10): In the following questions, the symbols #, $, @, * and © are used with the following meaning as illustrated below:
‘P # Q’ means ‘P is not smaller than Q’
‘P $ Q’ means `P is neither smaller than nor greater than Q’
‘P @ Q’ means `P is neither greater than nor equal to Q’
‘P * Q’ means `P is not greater than Q’
‘P © Q’ means ‘P is neither smaller than nor equal to Q’
Now in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true. Give answer
(a) if only Conclusion I is true.
(b) if only Conclusion II is true.
(c) if either Conclusion I or II is true.
(d) if neither Conclusion I nor II is true.
(e) if both Conclusions I and II are true.
- Statements:
B $ K, K @ D, D # M
Conclusions:
(I) B $ M
(II) B @ M
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Option: D
Explanation:
B = K ...(i);
K < D ...(ii);
D ≥ M ...(iii)
From (i) and (ii), we get
D > K = B ...(iv)
From (iii) and (iv), no specific relation can be obtained between B and M. Therefore, B = M (Conclusion I) and B < M (Conclusion II) are not necessarily true.
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- Statements:
H @ N, N © W, W # V
Conclusions:
(I) H @ V
(II) V @ N
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Option: B
Explanation:
H < N ... (i)
N > W ...(ii);
W ≥ V ...(iii)
From (ii) and (iii), we get
N > W ≥ V ...(iv)
From (i) and (iv), no specific relation can be obtained between H and V. Hence, H < V (Conclusion I) is not necessarily true. But V < N (Conclusion II) follows from equation (iv).
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- Statements:
J * D, Q # D, Q @ M
Conclusions:
(I) Q © J
(II) Q $ J
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Option: C
Explanation:
J ≤ D ...(i);
Q ≥ D ...(ii);
Q < M ...(iii)
Combining (i) and (ii), we get
Q ≥ D ≥ J
→ Q > J (Conclusion I) or Q = J (Conclusion II)
Hence, either conclusion I or conclusion II is true.
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- Statements:
F # G, N $ G, N © T
Conclusions:
(I) T © F
(II) N * F
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Option: B
Explanation:
F ≥ G ...(i);
N = G ... (ii);
N > T ... (iii)
Combining all, we get
F ≥ G = N > T
→ N ≤ F (Conclusion II) and T < F.
Hence, conclusion I (T > F) is not true but conclusion II is true.
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- Statements:
M © R, R @ K , K $ T
Conclusions:
(I) T © R
(II) T © M
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Option: A
Explanation:
M > R ...(i);
R < K ...(ii);
K = T ... (iii)
Combining (ii) and (iii), we get
K= T > R
→ T > R (Conclusion I).
On the basis of the given information no specific relation can be obtained between T and M. Hence, T > M (Conclusion II) is not necessarily true.
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