Hello and welcome to exampundit. Here is a set of Quant Quiz on Mixed Word Problems for IBPS Clerk Prelims 2018.
The following set of Quant Quiz consists 10 easy to moderate Word Problems with 8 minutes in hand.
[WpProQuiz 227]
Quant Quiz for IBPS Clerk Prelims 2018 for Revision
- At what rate of simple interest per annum a sum of money becomes 9/5 times itself in 8 years?
(A) 11%
(B) 12%
(C) 14 ½ %
(D) 10%
(E) None of these
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Option: D
Solution: suppose the sum of money is x & rate of interest is r.
ATQ ;
x + 2xr/25 = 9x/5
So, r =10%
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- In what time a sum of money will become 3 times itself @ 10% p.a. SI?
(A) 10 years
(B) 20 years
(C) 40 years
(D) Cannot be determined
(E) None of these
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Option: B
Solution: let the sum of money is x & time is t.
ATQ;
xt/10 = 3x - x
t= 20
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- A sum gets 5 times itself in 8 years at SI. In how many years will the sum become triples itself at the same rate of interest?
(A) 40 years
(B) 45 years
(C) 30 years
(D) 42 years
(E) None of these
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Option: A
Solution: suppose the sum of money is x, so the amount is 5x.
ATQ;
4x = 8xr/100
r= 50
So, in second case;
50tx/100 = 2x
T = 40 years
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- In how many years a sum of money becomes 5 times @ 8 % p.a. SI?
(A) 60
(B) 50
(C) 40
(D) 45
(E) 35
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Option: B
Solution:
ATQ,
4x= 8xt/100
x = 50
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- A sum of money has been divided between two sisters aged 13 years & 5.5 years such that they may get equal amounts when each of them will be 18 years old. If the money has been invested @ 10% p.a. SI , in what ratio the money will be invested for the sisters?
(A) 3:5
(B) 2:3
(C) 3:2
(D) 1:2
(E) 3:1
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Option: C
Solution:
ATQ;
5× x × 10 /100 + x = 12.5 × y × 10/100+y
So, x/y = 3/2
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- A sum of money has been invested in three parts at simple interest at the rate of 12%, 25%, 7% for 5 years, 4 years & 4 years respectively such that the amount received from each part is 64,000/-. Find the total sum.
(A) 1,00,000
(B) 84,000
(C) 1,20,000
(D) 2,00,000
(E) None of these
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Option: E
Solution:
1st part: x + (5*12*x)/100 = 64,000
x = 40,000
2nd part: y + (25*4*y)/100 = 64,000
y = 32,000
3rd part: z + (7*4*z)/100 = 64,000
z = 50,000
Total sum= 1,22,000/-
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- A sum of money becomes 12 times itself after 55 years @SI. In how many years will it become double?
(A) 4 years
(B) 5 years
(C) 6 years
(D) Cannot be determined
(E) None of these
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Option: B
Solution: ATQ,
x * 55 * r /100 = 11x
r = 20%
Then,
x * 20 * t /100 = x
t = 5 years
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- If SI on a certain sum of money for 5 years @ 15% p.a. SI is 1600/- less than the principal then find the SI.
(A) 4800/-
(B) 6400/-
(C) 2400/-
(D) 5000/-
(E) 5200/-
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Option: A
Solution: ATQ;
x - 1600 = x * 5 * 15 / 100
x = 6400/-
SI = 4800/-
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- A certain sum of money becomes 4 times itself in 6 years at what rate of interest?
(A) 20%
(B) 30%
(C) 40%
(D) 50%
(E) 60%
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Option: D
Solution:
ATQ;
x*r*6/100=3x
r = 50%
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- What would be the SI obtained on the amount of 2500/- at the rate of 10% p.a. after 2 years?
(A) 500/-
(B) 400/-
(C) 450/-
(D) 550/-
(E) 600/-
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Option: A
Solution:
SI = 2500 * 10 * 2 / 100
SI= 500/-
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