Hello and welcome to exampundit. So here is a set of SBI PO Prelims Quantitative Aptitude Quiz 2017.
1. √86.49+√(5+?^2)=27.3
1) 18
2) 22
3) 48
4) 20
5) 3√/5√28
2. Which of the following is almost same as 67.985×857.9×0.00063?
1) 6.7985×85.79×0.063
2) 67985×8579×63
3) 67.985×85.79×63
4) 3√/5√28
5) None
3.587.4+58.74×3-5.874/?=702.744
1) 2.136
2) 5.136
3) 8.325
4) 9.5
5) None of
the above
the above
4.9.4-[8.6-{6.4-(5.4-4.2-2)}]=?
1) 4
2) 8
3) 2
4) 0
5) 3√/5√28
5.42.33-3×42.32×15.3+3×42.3×15.32-15.32=?
1) 25699
2) 19683
3) 96873
4) 32593
5) None of
the above
the above
6. 2.273+3×1.232×2.27+3×2.272×1.23+1.233
1) 43
2) 63
3) 83
4) 23
5) None of
the above
the above
7. Which of the following is almost same as (6.4372×224.36)/(84.379×96.44)
1) (64372×22436)/(84379×9644)
2) (64372×22436)/(84.379×96.44)
3) (6.4372×224.36)/(84.379×96.44)
4) (8.4372×224.36)/(84.379×96.44)
5) none
8. √[(11.9×13.3×18.9)/(0.17×19×2.1)]=?
1) 63
2) 21
3) 17
4) 25
5) None of
the above
the above
9. √[(9.500×0.085×18.9)/(0.0017×0.19×2.1)]
1) 250
2) 350
3) 100
4) 150
5) None of
the above
the above
10. √[2000+√612+√196] =?
1) 45
2) 85
3) 25
4) 35
5) None of
the above
the above
Solutions – Tap to show
1. Ans-1
=9.3+√(7+?^2)=27.3
=>?^2=324-7
=>?=√317=17.88=18
2. Ans-1
The number of
decimals should be same for being equivalent. Here the number of decimal places
is 9. Option 1 has 9 decimal places . hence answer is 1
decimals should be same for being equivalent. Here the number of decimal places
is 9. Option 1 has 9 decimal places . hence answer is 1
3. Answer-1
=>5.874/?=587.4+117.48-702.744=2.136
4. Ans-1
=9.4-[8.6-{6.4-(3.2)}]=9.4-5.4=4
5. Ans-2
It is in the form of
(a-b)3=(42.3-15.3)3=273=19683
(a-b)3=(42.3-15.3)3=273=19683
6. Ans-1
It is in the form of
(a+b)3
(a+b)3
=(2.27+1.23)3=3.53=42.875≈43
7. Answer-3
For being equivalent
, the difference of the sum of number of decimal places in numerator and
denominator should be same
, the difference of the sum of number of decimal places in numerator and
denominator should be same
Here the decimal
places in numerator=6 and in denominator is 5, difference is 1 . and in option
3 also the difference is 1. Hence they are equal.
places in numerator=6 and in denominator is 5, difference is 1 . and in option
3 also the difference is 1. Hence they are equal.
8. Ans-2
When the sum of
decimal places in numerator is equal to that in denominator under the radical
sign, the decimals get removed
decimal places in numerator is equal to that in denominator under the radical
sign, the decimals get removed
√[(11.9×13.3×18.9)/(0.17×19×2.1)]=
√ [(119×133×189)/(17×19×21)]= V(7×7×9)=21
√ [(119×133×189)/(17×19×21)]= V(7×7×9)=21
9. Ans-4
When the sum of
decimal places in numerator is equal to that in denominator under the radical
sign, the decimals get removed..but the extra zeroes added after decimal to equalize
the decimal places in numerator and denominator is taken into calculation. Here
9.5 was taken as 9.500 hence after removing decimals it will be 9500
decimal places in numerator is equal to that in denominator under the radical
sign, the decimals get removed..but the extra zeroes added after decimal to equalize
the decimal places in numerator and denominator is taken into calculation. Here
9.5 was taken as 9.500 hence after removing decimals it will be 9500
√[(9500×85×189)/(17×19×21)]= √(500×5×9)=150
10. Ans-1
√[2000+√612+13]=√2000+25=
45
45
ep
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