Hello and welcome to exampundit. Here is a set of Puzzle Quiz for SBI PO Prelims 2017.
Questions 1 to 3:
Four friends are sitting at the
four sides of a square table at a Café. Eighteen cookies and many sachets of
sugar, all of equal size, are kept at the table. The one opposite Sam has black
coffee with twice as many sachets of sugar as him and three cookies more than
him. Joe has half as many sachets of sugar but twice as many cookies as the one
opposite him. Sam has the same number of cookies as one of his friends. Raman
has more sugar in his coffee than Arun and also adds milk to it. No one uses a
sachet partially or has more than four sachets.
four sides of a square table at a Café. Eighteen cookies and many sachets of
sugar, all of equal size, are kept at the table. The one opposite Sam has black
coffee with twice as many sachets of sugar as him and three cookies more than
him. Joe has half as many sachets of sugar but twice as many cookies as the one
opposite him. Sam has the same number of cookies as one of his friends. Raman
has more sugar in his coffee than Arun and also adds milk to it. No one uses a
sachet partially or has more than four sachets.
1. How does Arun have his coffee?
1) Black, with 1 sachet of sugar
2) With milk and 3 sachets of
sugar
sugar
3) Black, with 2 sachets of sugar
4) Cannot be determined
2. Which of the following is
true?
true?
1) The one opposite Arun uses 2
sachets of sugar less than him.
sachets of sugar less than him.
2) The one opposite Raman eats 3
cookies more than him.
cookies more than him.
3) The one opposite Joe uses 1
sachet of sugar more than him.
sachet of sugar more than him.
4) The one opposite Sam eats 5
cookies.
cookies.
3. Which of the following is
false?
false?
1) Arun sits next to someone who
uses same number of sachets as him.
uses same number of sachets as him.
2) Joe sits next to someone who
eats the same number of cookies as him.
eats the same number of cookies as him.
3) Raman sits next to someone who
uses same number of sachets as him.
uses same number of sachets as him.
4) Sam sits next to someone who
eats the same number of cookies as him.
eats the same number of cookies as him.
Questions 4 to 7:
Eight members of a trekking club
– A, B, C, D, E, F, G and H – plan to go trekking this weekend. Two
simultaneous treks – Trek I and Trek II – are planned, each of which will have
exactly 4 participants. A, C and G are doctors. A, B, E and H have prior
trekking experience. It is decided that each group should have at least 1
doctor and 2 members with prior experience. Also B and C must be in different
groups.
– A, B, C, D, E, F, G and H – plan to go trekking this weekend. Two
simultaneous treks – Trek I and Trek II – are planned, each of which will have
exactly 4 participants. A, C and G are doctors. A, B, E and H have prior
trekking experience. It is decided that each group should have at least 1
doctor and 2 members with prior experience. Also B and C must be in different
groups.
4. If D and F insist in going on
Trek II, which of the following must also go on Trek II?
Trek II, which of the following must also go on Trek II?
1) G
2) E
3) B
4) H
5. If F and C go on Trek II, then
in how many ways can the group for Trek I be formed?
in how many ways can the group for Trek I be formed?
1) 1 way
2) 2 ways
3) 3 ways
4) No such group possible
6. If A is the only doctor in his
group, then which of the following is necessarily true?
group, then which of the following is necessarily true?
1) B and G go on the same trek.
2) E and G go on different treks.
3) D and F go on the same trek.
4) D and F go on different treks.
7. If A and B go on different
treks, which of the following could be true?
treks, which of the following could be true?
1) A and G go on the same trek.
2) D and F go on the same trek.
3) E and H go on the same trek.
4) F and H go on the same trek.
Answers & Solutions:
Question 1 to 3:
- 3
- 2
- 3
We first make an elementary
table:
table:
Number of cookies with Sam must
be m or 2m. But if it is 2m then we get 7m + 3 = 18 which is not possible. So,
Sam has m cookies with m = 3 (5m + 3 = 18). Also, Raman adds milk so he cannot
be opposite to Sam. And since Raman has more sugar than Arun, 2y > 2x. The
only possibility then is x = 1, 2x = y = 2, 2y = 4. We thus get the complete
table:
be m or 2m. But if it is 2m then we get 7m + 3 = 18 which is not possible. So,
Sam has m cookies with m = 3 (5m + 3 = 18). Also, Raman adds milk so he cannot
be opposite to Sam. And since Raman has more sugar than Arun, 2y > 2x. The
only possibility then is x = 1, 2x = y = 2, 2y = 4. We thus get the complete
table:
4. Neither D nor F have prior experience,
and neither is a doctor. So the only way to fulfil the given conditions is if
A, who also has prior experience, goes as the doctor, while the 4th member also
has prior experience. Thus the other doctors, C and G, must go on Trek I, and B
must be on Trek II. Hence (3).
and neither is a doctor. So the only way to fulfil the given conditions is if
A, who also has prior experience, goes as the doctor, while the 4th member also
has prior experience. Thus the other doctors, C and G, must go on Trek I, and B
must be on Trek II. Hence (3).
5. If F and C go on Trek II, B
must go on Trek I. Trek II requires the remaining 2 people to have prior
experience and hence D and G also must go on Trek I. Now, any one of the three
remaining people with prior experience (A, E and H) can be sent on Trek I and
the other two on Trek II. Hence 3 ways. Hence (3).
must go on Trek I. Trek II requires the remaining 2 people to have prior
experience and hence D and G also must go on Trek I. Now, any one of the three
remaining people with prior experience (A, E and H) can be sent on Trek I and
the other two on Trek II. Hence 3 ways. Hence (3).
6. If A is the only doctor in his
group, C and G must be in the other group. Thus B must be in the first group. Also,
the other two with C and G must be having prior experience. Thus they must be E
and H, while D and F must go with A and B. Hence (3).
group, C and G must be in the other group. Thus B must be in the first group. Also,
the other two with C and G must be having prior experience. Thus they must be E
and H, while D and F must go with A and B. Hence (3).
7. Since both A and C cannot go
with B, they must be together. Hence the remaining doctor, G, must go with B.
Also, each group has only one experienced person so far, and hence E and H must
go to different groups. Similarly the fourth spot in each group must be taken
by D and F, one to each group. Hence the options (1), (2) and (3) are all
impossible, but option (4) could take place (for example Trek I – A, C, D, E
and Trek II – B, F, G, H is a possible combination). Hence,(4).
with B, they must be together. Hence the remaining doctor, G, must go with B.
Also, each group has only one experienced person so far, and hence E and H must
go to different groups. Similarly the fourth spot in each group must be taken
by D and F, one to each group. Hence the options (1), (2) and (3) are all
impossible, but option (4) could take place (for example Trek I – A, C, D, E
and Trek II – B, F, G, H is a possible combination). Hence,(4).
ep
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