Hello and welcome to exampundit. Here is a set of Puzzle for SBI PO Mains 2017.
Directions for
questions 1 to 5: Answer the questions on the basis of the information
given below:
questions 1 to 5: Answer the questions on the basis of the information
given below:
K, L, M, N, P, Q, R, S, U and W are the only ten members in
a department. There is a proposal to form a team from within the members of the
department, subject to the following conditions:
a department. There is a proposal to form a team from within the members of the
department, subject to the following conditions:
1. A team must include exactly one among P, R, and S.
2. A team must include either M or Q, but not both.
3. If a team includes K, then it must also include L, and
vice versa.
vice versa.
4. If a team includes one among S, U, and W, then it must
also include the other two.
also include the other two.
5. L and N cannot be members of the same team.
6. L and U cannot be members of the same team.
The size of a team is defined as the number of members in
the team.
the team.
1. Who cannot be a member of a team of size 3?
(1) L
(2) M
(3) N
(4) P
(5) Q
2. Who can be a member of a team of size 5?
(1) K
(2) L
(3) M
(4) P
(5) R
3. What would be the size of the largest possible team?
(1) 8
(2) 7
(3) 6
(4) 5
(5) Cannot be determined
4. What could be the size of a team that includes K?
(1) 2 or 3
(2) 2 or 4
(3) 3 or 4
(4) Only 2
(5) Only 4
5. In how many ways a team can be constituted so that the
team includes N?
team includes N?
(1) 2
(2) 3
(3) 4
(4) 5
(5) 6
Answers:
For questions 1 to 5:
From statement one, team would include exactly one among P,
R, S
R, S
⇒ P (or) R (or) S.
From statement two, team would include either M, or Q
⇒ M but not Q
(or) Q but not M
From statement three, if a team includes K, it will include
L or vice versa.
L or vice versa.
⇒ K, L always accompany each other.
From statement four, if one of S, U, W is included, then the
other two also have to be included.
other two also have to be included.
⇒ S, U, W are always together.
From statement five, L and N cannot be included together
⇒ L, N are never together.
From statement six, L and U cannot be included together.
⇒ L, U are never together.
1. 1 From statements one and two; one of P, R, S and one of
M, Q are to be selected. We require one more member.
M, Q are to be selected. We require one more member.
But from statement three; (K, L) are always together.
Hence ‘L’ cannot be included in a team of 3 members.
2. 3 Again, from statement one; one of P, R, S has to be
selected.
selected.
To make a team of ‘5’
‘S’ will be chosen (which leaves out P and R)
⇒ If ‘S’ is chosen ‘U’ and ‘W’ have to be chosen
(statement four)
⇒ If ‘U’ is chosen ‘L’ cannot be chosen (statement five)
⇒ K cannot be chosen (statement three)
And from statement two; one of M (or) Q has to be chosen.
3. 4 From statements one and two
Two members are to be selected.
Of the remaining seven;
To maximize the size of the team.
We would chose S,
⇒ U and W are included in the team (statement four)
We cannot include K (or) L because we would then have to
leave out N and U (from statements five and six)
leave out N and U (from statements five and six)
4. 5 If ‘K’ is included, ‘L’ has to be included (statement
(3))
(3))
If ‘L’ is chosen, neither N nor U can be chosen (statements
(5) and (6))
(5) and (6))
⇒ S, W are also not included because S, U, W have to be
always together. (Statement (4))
always together. (Statement (4))
Hence one of P (or) R would be selected (statement
(1)) and one of M (or) Q would be selected (statement (2))
(K, L) and two of the
above five have to be included.
above five have to be included.
5. 5 If a team includes N, it cannot include ‘L’, and
therefore, not even ‘K’. (from statement five and three)
therefore, not even ‘K’. (from statement five and three)
According to statement (1), one of P or R or S has to be
included.
included.
According to statement (2), one of M or Q has to be selected.
So the following cases are possible
P Q N,
R Q N
P M N,
R M N
If ‘S’ is selected, then S U W M N and S U W Q N are the only
possible cases.
possible cases.
Hence, in all 4 + 2 = 6 teams can be constituted.
ep
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