# SBI Clerk 2018: Quantitative Aptitude Quiz for Prelims – 14

Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz on Age Based Problems for Prelims exam of SBI Clerk 2018.

1. In a class there are 60 girls whose total age is 1500 years. The average age of 20 girls is 12 years and that of another 20 girls is 16 years. Find the average age of remaining girls?
(a) 48 years
(b) 49 years
(c) 47 years
(d) 51 years

Option: C

Explanation: Average age of remaining girls={1500-(20*12+20*16)}/(60-20-20)
=(1500-240-320)/20=940/20=47 years

2. The average age of 35 boys is 25 years. If the age of one more boy is added to it,the average increases by 2 years. What is the age of new boy?
(a) 97
(b) 99
(c) 96
(d) 95

Option: A

Explanation: Let the age of new boy be x years. According to the question,total age of 35 boys=35*25=875 years.
Accordingly we are getting an equation like this: (35*25)+x/36=(25+2)
Or 875+x/36=27
Or x=97 years.

3. The ratio of ages of Ram and Sita is 4:3. After 4 years,this ratio will be 9:7. If at the time of marriage ,the ratio was 5:3,then find out for how many years were they married?
(a) 10 years
(b) 8 years
(c) 15 years
(d) 12 years

Option: D

Explanation: Let the present ages of Ram and Sita be 4x and 3x years
We get 4x+4/3x+4=9/7
Or 7*(4x+4)=9*(3x+4)
Or x=8
Thus we find out their present ages that is 32 years and 24 years.
Lets consider they were married y years ago,
So 32-y/24-y=5/3
or 3*(32-y)=5*(24-y)
or 2z=24
or z=12 years

4. Ranveer stays with his father,mother and a younger brother who is 4 years younger to him. His father was 38 years of age when Ranveer was born while his mother was 36 years when his brother was born. Find out the difference of ages of his parents.?
(a) 6 years
(b) 2 years
(c) 4 years
(d) 8 years

Option: A

Explanation: Mother’s age when Ranveer’s brother was born=36 years
Father’s age when Ranveer’s brother was born=38+4=42 years
Therefore,Required difference=(42-36)=6 years.

5. Rajesh is as more younger to Amitabh as Rajesh is older to Pranay. If the sum of the ages of Amitabh & Pranay is 48 years. What is the age of of Rajesh in years?
(a) 26 years
(b) 27 years
(c) 28 years
(d) 24 years

Option: D

Explanation: Let the age of Rajesh is x years
Amitabh be y years
Pranay be z years
y-x=x-z
or 2x=y+z
=48
Or x=24 years
Thus age of Rajesh is 24 years.

6. Renuka got married 10 years ago. Her present age is 1.2 times her age at the time of her marriage. Renuka’s brother was 8 years younger to her at the time of her marriage. The age of Renuka’s brother is?

(a) 53 years
(b) 52 years
(c) 51 years
(d) 54 years

Option: B

Explanation: Let Renuka’s present age be x years. Her age at the time of marriage was=(x-10) years. Therefore
X=1.2(x-10)
Or 0.2 x=12
Or x=60.
Renuka’s brother’s age at the time of her marriage=(x-10)-8=(x-18)years=(60-18)=42 years.
So,Renuka’s brother’s present age=42+10=52 years.

7. If 6 years are subtracted from the present age of Rohit and the remainder is divided by 18,then the present age of his grand daughter Raima is obtained. If Raima is 2 years younger to Anushka whose age is 5 years,then deduce Rohit’s present age?
(a) 48 years
(b) 60 years
(c) 84 years
(d) 96 years

Option: B

Explanation: Raima’s age from problem is (5-2) years=3 years. Let Rohit’s age be x years.
Therefore we get, (x-6)/18=3
Or x-6=54
Or x=60 years

8. The total ages of Messi,Ronaldo and Neymar is 93 years. Ten years ago,the ratio of their ages was 2:3:4. What is the ratio of present ages of Messi and Neymar?
(a) 48:76
(b) 19:12
(c) 13:65
(d) 34:67

Option: A

Explanation: Let the ages of Messi,Ronaldo and Neymar 10 years be 2x,3x and 4x years respectively
Then,(2x+10)+(3x+10)+(4x+10)=93
Or 9x+30=93
Or 9x=63
Or x=7

Present age of Messi=2x+10=2*7+10=14+10=24
Present age of Neymar=4x+10=4*7+10=28+10=38
Ratio of present ages of Messi and Neymar=24/38=48/76.

9. The ratio of Savitri’s age to her father is 3:11. The difference of their ages is 24 years. What will be the ratio of their ages after 3 years?
(a) 2:1
(b) 3:1
(c) 1:3
(d) 2:3

Option: C

Explanation: Difference in ratios=8(11-3)
Then 8 is equivalent to 24 and 1 is equivalent to 3 (Value of 1 in ratio is equivalent to 3 years)
Therefore,Savitri’s age=3*3=9 years
Father’s age=11*3=33 years
After 3 years,the ratio=12:36=1:3

10. Federer’s age is 125% of what it was 10 years ago,but (250/3)% of what it will be after 10 years. What is his present age?
(a) 60 years
(b) 75 years
(c) 45 years
(d) 50 years

Option: D

Explanation: Let the present age of Federer be x years. Then 125%of(x-10)=x and (250/3)% of (x+10)=x
Now we equate both the equations, 125%of(x-10)= (250/3)% of (x+10)
Or (5/4)*(x-10)=(5/6)*(x+10)
Or 5x/4-5x/6=50/6+50/4
Or 5x/12=250/12
Or x=50 years

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