Reasoning Quiz for SBI PO Mains 2016 – Set 3


Hello and welcome to exampundit . Here is a set of Reasoning Quiz for SBI PO Mains 2016.

Directions (Q. 1-5):
Study the following information carefully and answer the questions given below
it:

Six lectures — A, B, C, D, E and F — are to be delivered
from Monday to Sunday, one lecture every day.
(i) Lecture C cannot be delivered on Friday.
(ii) Lecture A is delivered immediately after lecture D.
(iii) There should be a gap of two days between the lectures
B and F.
(iv) There is one holiday except Saturday. Lecture F is
delivered on the next day of holiday.
(v) Lecture E is delivered on Wednesday and it is not immediately
followed by lecture F.
1. On which day was
lecture D delivered?
1) Friday
2) Saturday
3) Sunday
4) Thursday
5) None of these
2. On which day was
holiday?
1) Sunday
2) Friday
3) Monday
4) Can’t be determined
5) None of these
3. How many lectures
were delivered between F and D?
1) None
2) One
3) Two
4) Three
5) None of these
4. Which of the
following was the last lecture?
1) A
2) C
3) B
4) Can’t be determined
5) None of these
5. Which of the
following statements is not necessary to determine the order of lectures?
1) (i)
2) (ii)
3) (v)
4) (i) and (ii)
5) All statements are necessary

Solutions – From clue (v): Lecture E is delivered on Wednesday. And the
lecture F was not delivered on Thursday. Again, from clue (iv): Tuesday and
Saturday were not holiday. From direction part it is obvious that neither
Monday nor Sunday was holiday. So, by elimination holiday was either on
Thursday or on Friday.

Now, from clues (iii) and (iv) we get the following orders
of lectures of B and F X.
B * Holiday F Y.
Holiday F * * B
Reject the possibility ‘Y’ because according to it there
must be at least four lectures after holiday. This is not possible even when
the holiday is on Thursday. Now, use the possibility ‘X’. If holiday is on
Friday, two lectures (B & E) need to be arranged on Wednesday, which is not
possible.
Therefore, the holiday must be on Thursday. And the lectures
B and F delivered on Tuesday and Friday respectively.
Now, from clue (ii): A can’t be delivered either on Monday
or on Saturday. Obviously, the lecture A was delivered on Sunday. This implies
that the lecture D was delivered on Saturday. By elimination, the lecture C was
delivered on Monday.
Thus, the whole information can be tabulated as below:
Day
Lecture
Monday
C
Tuesday
B
Wednesday
E
Thursday
Holiday
Friday
F
Saturday
D
Sunday
A

  

Directions (Q. 6-7):
Study the information given below to answer these questions.
I. There is a family of five persons A, B, C, D and E.
II. They are working as a doctor, a teacher, a trader, a
lawyer and a farmer.
III. B, an unmarried teacher, is the daughter of A.
IV. E, a lawyer, is the brother of C.
V. C is the husband in the only married couple in the
family.
VI. A, a farmer, is a father of two sons and an unmarried
daughter.
VII. The daughter-in-law of A is a doctor.
6. Which of the
following is a group of female members in the family?
1) D and E
2) B and D
3) A, C and E
4) B and C
5) None of these
7. Which of the
following is the married couple?
1) C and D
2) A and B
3) A and D
4) B and D
5) None of these

Solutions –
Directions (Q.8-10):
Study the following information carefully and answer the given questions:
In a certain code ‘colours of the
sky’ is written as ‘ki la fa so’, ‘rainbow colours’ is written as ‘ro ki’ and
‘sky high rocket’ is written as ‘la pe jo’ and ‘the rocket world’ is written as
‘pe so ne’.
8. Which of the
follwing will/may represent ‘the’?
1) Only ‘fa’
2) Either ‘fa’or ‘la’
3) Only ‘so’
4) Only ‘la’
5) Either ‘so’ or ‘fa’
9. What does ‘pe’
respresent in the code?
1) colours
2) sky
3) high
4) rainbow
5) rocket
10. Which of the
following is the code for ‘colours sky high’?
1) ro jo lo
2) fa lo jo
3) la ki so
4) ki jo la
5) fa ki jo

Solutions –   

colours
sky
of
the
rainbow
high
rocket
world
ki
la
fa
so
ro
jo
pe
ne



Regards

function answer(id){
if(document.getElementById(id).style.display == “block”){
document.getElementById(id).style.display = “none”;
}else{
document.getElementById(id).style.display = “block”;
}
}

#a1{display:none;}
#a2{display:none;}
#a3{display:none;}

Team ExamPundit

Average rating / 5. Vote count:

We are sorry that this post was not useful for you!

Let us improve this post!