Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz for NIACL AO 2018 Prelims on Quadratic Equations Problems.

Along with Reasoning, We will be providing good level Quantitative Aptitude Problems. Quantitative Aptitude needs a lot of practice and calculations. We have already given you an article on How to Score Maximum in Quantitative Aptitude. These Quantitative Aptitude quizzes will help you get past NIACL AO Prelims exam.

Quantitative Aptitude Quiz for NIACL AO Prelims 2018

The following Quantitative Aptitude Quiz has 10 questions from Quadratic Equations Problems with 8 minutes.

Time limit: 0

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The following questions are created as per the recent trends and level of NIACL AO Prelims 2018.

Test Name: Quantitative Aptitude Quiz for NIACL AO Prelims 2018

Duration: 8 min

Level: Moderate

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Question 1 of 10

1. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer

4X² -43X +105=0

7Y² -29Y +30=0

Correct

4X² -28X -15X + 105=0

X= 7, 3.75

7Y² – 29Y + 30=0

7Y² – 14Y -15Y +30=0

Y= 2, 2.142

X>Y

Incorrect

4X² -28X -15X + 105=0

X= 7, 3.75

7Y² – 29Y + 30=0

7Y² – 14Y -15Y +30=0

Y= 2, 2.142

X>Y

Question 2 of 10

2. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer

8X² -49X +45= 0

8Y² -Y -9 =0

Correct

8X² – 40X – 9X +45= 0

X= 5, 1.1

8Y² – Y -9=0

8Y² +8Y – 9Y – 9= 0

Y= 1.1 , -1

X≥Y

Incorrect

8X² – 40X – 9X +45= 0

X= 5, 1.1

8Y² – Y -9=0

8Y² +8Y – 9Y – 9= 0

Y= 1.1 , -1

X≥Y

Question 3 of 10

3. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer

X² -82X + 781= 0

Y² = 5041

Correct

X² – 71X – 11X – 781= 0

X= 71, 11

Y²= 5041

Y= +71, -71

CAN’T BE DETERMINED.

Incorrect

X² – 71X – 11X – 781= 0

X= 71, 11

Y²= 5041

Y= +71, -71

CAN’T BE DETERMINED.

Question 4 of 10

4. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer

3X² – ( 6+√17) X + 2√17= 0

5Y² – (15-√17) Y – 3√17= 0

Correct

3X² – 6X – √17 X + 2√17= 0

X= 2, √17/3

5Y² – (15-√17)Y – 3√17= 0

5Y² -15Y +√17Y – 3√17= 0

Y= 3, -√17/3

CAN’T BE DETERMINED

Incorrect

3X² – 6X – √17 X + 2√17= 0

X= 2, √17/3

5Y² – (15-√17)Y – 3√17= 0

5Y² -15Y +√17Y – 3√17= 0

Y= 3, -√17/3

CAN’T BE DETERMINED

Question 5 of 10

5. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer

63X – 94√X +35= 0

32Y -52√Y +21 = 0

Correct

63X – 94√X + 35= 0

63X – 45√X – 49√X + 35= 0

X= 25/49, 49/81

32Y – 52√Y + 21= 0

32Y – 24Y√Y – 28√Y + 21= 0

Y= 9/16, 49/64

CAN’T BE DETERMINED.

Incorrect

63X – 94√X + 35= 0

63X – 45√X – 49√X + 35= 0

X= 25/49, 49/81

32Y – 52√Y + 21= 0

32Y – 24Y√Y – 28√Y + 21= 0

Y= 9/16, 49/64

CAN’T BE DETERMINED.

Question 6 of 10

6. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer:

12X² – 47X + 40=0

4Y² + 3Y – 10= 0

Correct

12= 3 * 4 40= 8 * 5

12X² – 32X – 15X + 40 = 0

X= 32/12= 8/3= 2.66

X= 15/12= 5/4 = 1.25

4Y² + 3Y – 10= 0

4= 4 * 1 10= 5 * 2

4Y² + 8Y – 5Y – 10= 0

Y= – 8/2= -4

Y= 5/4 = 1.25

X≥Y

Incorrect

12= 3 * 4 40= 8 * 5

12X² – 32X – 15X + 40 = 0

X= 32/12= 8/3= 2.66

X= 15/12= 5/4 = 1.25

4Y² + 3Y – 10= 0

4= 4 * 1 10= 5 * 2

4Y² + 8Y – 5Y – 10= 0

Y= – 8/2= -4

Y= 5/4 = 1.25

X≥Y

Question 7 of 10

7. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer:

13X – 8Y + 81= 0

15X – 5Y + 65= 0

Correct

13X – 8Y = -81 …………… *5

15X – 5Y = – 65 …………….. *8

65X – 40Y = -81 * 5

120X – 40Y = -65 * 8

X= – 2.09

Y= POSITIVE VALUE

X<Y

Incorrect

13X – 8Y = -81 …………… *5

15X – 5Y = – 65 …………….. *8

65X – 40Y = -81 * 5

120X – 40Y = -65 * 8

X= – 2.09

Y= POSITIVE VALUE

X<Y

Question 8 of 10

8. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer:

15X² – 46X + 35=0

4Y² – 15Y +14= 0

Correct

15= 5 * 3 35= 7 * 5

15X² – 46X + 35=0

15X² – 25X – 21X + 35= 0

X= 25/15= 1.66

X= 21/15= 1.4

4Y² – 15Y +14= 0

4Y² – 8Y – 7Y + 14= 0

Y= 8/4= 2

Y= 7/4= 1.75

X<Y

Incorrect

15= 5 * 3 35= 7 * 5

15X² – 46X + 35=0

15X² – 25X – 21X + 35= 0

X= 25/15= 1.66

X= 21/15= 1.4

4Y² – 15Y +14= 0

4Y² – 8Y – 7Y + 14= 0

Y= 8/4= 2

Y= 7/4= 1.75

X<Y

Question 9 of 10

9. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer:

20X² – 67X + 56= 0

56Y² – 67Y + 20= 0

Correct

20X² – 67X + 56= 0

20X² – 35X – 32X + 56= 0

X= 7/4= 1.75

X= 8/5= 1.6

56Y² – 67Y + 20= 0

56Y² – 32Y – 35Y +20= 0

Y= 4/7= 0.57

Y= 5/8= 0.625

X>Y

Incorrect

20X² – 67X + 56= 0

20X² – 35X – 32X + 56= 0

X= 7/4= 1.75

X= 8/5= 1.6

56Y² – 67Y + 20= 0

56Y² – 32Y – 35Y +20= 0

Y= 4/7= 0.57

Y= 5/8= 0.625

X>Y

Question 10 of 10

10. Question

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer:

35X² – 56X +20= 0

56Y² – 97Y +42= 0

Correct

35X² – 56X +20= 0

35X² – 28X – 25X + 20= 0

X= 4/5= 0.8

X= 5/7= 0.7

56Y² – 97Y +42= 0

56Y² – 48Y – 49Y + 42= 0

Y= 6/7= 0.85

Y= 7/8= 0.87

X<Y

Incorrect

35X² – 56X +20= 0

35X² – 28X – 25X + 20= 0

X= 4/5= 0.8

X= 5/7= 0.7

56Y² – 97Y +42= 0

56Y² – 48Y – 49Y + 42= 0

Y= 6/7= 0.85

Y= 7/8= 0.87

X<Y

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