Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Questions based on Mixed Word Problems.
the marked price of an article but charges a sales tax of 5% on the discounted
price. If Sita, a customer pays Rs. 718.2 as including the sales tax, then what
is the marked price?
in lieu of getting more gain. He mixes 24 kg of sugar worth Rs. 35 per kg with
another quality of sugar of Rs.42 per kg. By selling the mixture at Rs. 41.04
per kg, he may gain 8%. How much sugar of second quality has been added to the
mixture?
while crossing rivers. Once while crossing a river, he observes that he can row
11 2/3 kmph in still water and finds
that it takes six times more to row up than to row down the same distance in
the river. What is the speed of the current?
present age of Amit is equal to the average ages of Akhil and Anil after 2
years. If the ratio of present age of Amit and age of Anil after four years is
6 : 7 then what will be the ratio of age of Akhil after four years to that of
present age of Amit?
share in the ratio 7/2:4/3:6/5. After 4 months, Deepak increases his share by
50%. If the total profit at the end of one year be 43200, then Dheeraj’s share
in the profit is _______
km/hr and with stoppages it covers the same distance at an average speed of 75
km/hr. How many minutes per hour does the car stops ?
digits 1, 2, 3, 4, 5, 6, 7, 8, 9 when only numbers of 3 digits are formed and
when repetitions are not allowed.
Ranchi to Kolkata at 64 km/hr and returns to Ranchi at a slower speed. If its
average speed for the whole journey is 56 km/hr, at what speed did it return ?
equal annual installments of 882,
allowing 5% compound interest. The sum borrowed was ?
probability of their winning are 1/7 and 1/3 respectively. Find the probability
that neither of them will win the race ?
- A
- C
- D
- A
- C
- B
- A
- B
- D
- D
Solutions:
1. Total discount=10+5-(10×5/100)=14.5%
SP+SP(5/100)= 718.2
=>105 SP/100=718.2
SP=684
MP=684/(100-14.5) x100=800
2. Actual price of mixture=41.04/1.08= 38
Amount of sugar added of 2nd quality = (24×3)/4=18kg
3. Let distance=d
Speed of the current =x kmph
Given d/[(35/3)-x]=6d/[35/3)+x]
Or 70-6x=(35/3)+x
=>7x=175/3
=>x=25/3=8 1/3 kmph
4. Let the age of Akhil and Anil be 7x and 9x
Amit ‘s age=(7x+2+9x+2)/2=8x+2
Given (8x+2)/(9x+4)=6/7
=>x=7
Akhil=35
Amit=42
Anil=45
Required ratio=(35+4)/42=39/42=13:14
5. Given ratio=7/2:4/3:6/5=105 : 40 : 36
Ratio of investments (i.e. ratio of profit) =
[105×4 + (150 % of 105) × 8] : (40 × 12) : ( 36 × 12)= 1680 : 480 : 432 = 35 : 10 : 9
=> Dheeraj’s share in the profit=9/(35+10+9) x43200= 7200
6. Let, the distance = 60 km.
When speed is 90 km/hr. the time taken =60/90 h = 40 minutes
When speed is 75 km/hr. the time taken = 60/75=48 minutes
Stoppage=4840=8 minutes
7. 2/(9*8*7)=2/504=1/252
8. 2*64*x/(64+x)=56
=>x=(64*56)/72=49.77 kmph
9. sum =882/(1+5/100) + 882/(1+5/100)^2
=882/(105/100) + 882/(105/100)^2
=882/(21/20) + 882/ (21/20)^2 =1640
10. 1-[(1/7)+(1/3)]=1-(10/21)=11/21
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