New Pattern Inequalities- 4 – Quantitative Aptitude Quiz 2019

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Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz for SBI PO Prelims 2019 on New Pattern Inequalities Problems.

Along with Reasoning, We will be providing good level Quantitative Aptitude Problems. Quantitative Aptitude needs a lot of practice and calculations. We have already given you an article on How to Score Maximum in Quantitative Aptitude. These Quantitative Aptitude quizzes will help you get past SBI PO Prelims 2019.

New Pattern Inequalities – 3 – Quantitative Aptitude Quiz 2019

The following Quantitative Aptitude Quiz has 10 questions from New Pattern Inequalities ( Quantity 1 and Quantity 2) Problems with 8 minutes.

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The following questions are created as per the recent trends and level of SBI PO Prelims 2019.

Test Name: New Pattern Inequalities Quiz for SBI PO Prelims 2019

Duration: 8 min

Level: Moderate

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Question 1 of 8

1. Question

Find the original consumption if

Quantity 1: After increasing price by 20% a family now gets 10kg less on that price.

Quantity 2: After increasing price by 25% a family increases expenditure by 15% and gets 5 kg less than original consumption.

Correct

Q1: 20% increase= 1/5

1/( 1+5) * T= 10

T= 60

Q2: 100

115 125

125-115= 10

10/125 * T=5

T= 62.5

Quantity 1< Quantity 2

Incorrect

Q1: 20% increase= 1/5

1/( 1+5) * T= 10

T= 60

Q2: 100

115 125

125-115= 10

10/125 * T=5

T= 62.5

Quantity 1< Quantity 2

Question 2 of 8

2. Question

A and B started a business with Rs. 10000 and Rs. 16000 respectively. After 5 months C joined them with Rs. 18000. Total profit is Rs. 14600 after a year.

A can do a work in 15 days. B is 25% more efficient than A

Quantity 1: Time taken by A and B together to do the work.

Quantity 2: No of days of C to do the work if the efficiency of C is 20% more than B.

Correct

A can do the work in 15 days

100 * 15= 125 * D

D= 100*15/125 = 12

B can do a work in 12 days

Q1: A and B together can do= 1/15 + 1/12= 9/60 = 3/20

Q2: 100 * 12= 120 * D

D= 100*12/120 = 10

Quantity 1 > Quantity 2

Incorrect

A can do the work in 15 days

100 * 15= 125 * D

D= 100*15/125 = 12

B can do a work in 12 days

Q1: A and B together can do= 1/15 + 1/12= 9/60 = 3/20

Q2: 100 * 12= 120 * D

D= 100*12/120 = 10

Quantity 1 > Quantity 2

Question 4 of 8

4. Question

A man can row 15 kmph in still water. It takes him thrice as long to row up as to row down the river.

Quantity 1: Rate of stream

Quantity 2: Speed of stream if upstream speed is 15 kmph and downstream speed is310 kmph.

Correct

5+x= 3(15-X)

15+ x= 45 – 3x

4x= 30

X= 7.5

Q1: 7.5 kmph

Q2: Speed of stream= (30-15)/2 =15/2= 7.5

Quantity 1= Quantity 2

Incorrect

5+x= 3(15-X)

15+ x= 45 – 3x

4x= 30

X= 7.5

Q1: 7.5 kmph

Q2: Speed of stream= (30-15)/2 =15/2= 7.5

Quantity 1= Quantity 2

Question 5 of 8

5. Question

Three equations are given in each question. You have to decide the relation between the three equations:

1) X= √[ (36)^1/2 * (1296)^1/4]

2) 2Y + 3Z= 33

3) 6Y + 5Z= 71

Correct

1) X= √[ 6 * 6) = 6

6Y + 9Z= 99By solving equation: Z= 7

6Y + 5Z= 71 Y= 6

X= 6 Y=6 Z=7

Incorrect

1) X= √[ 6 * 6) = 6

6Y + 9Z= 99By solving equation: Z= 7

6Y + 5Z= 71 Y= 6

X= 6 Y=6 Z=7

Question 6 of 8

6. Question

Three equations are given in each question. You have to decide the relation between the three equations:

1) 8X + 7Y= 135

2) 5X + 6Y= 99

3) 9Y + 8Z= 121

Correct

By equation 1) * 5 – 2) * 8

40X + 35Y= 675Y=9 X= 9

40X +48Y = 792

From equation 3)

9 * 9 + 8Z = 121

Z= 5

X = Y >Z

Incorrect

By equation 1) * 5 – 2) * 8

40X + 35Y= 675Y=9 X= 9

40X +48Y = 792

From equation 3)

9 * 9 + 8Z = 121

Z= 5

X = Y >Z

Question 7 of 8

7. Question

Three equations are given in each question. You have to decide the relation between the three equations:

1) X+ 3Y + 4Z= 96

2) 2X + 8Z= 80

3)2X + 6Y= 120

Correct

By equation 1) * 2 – 2)

2X + 6Y + 8Z = 96*2

2X + 8Z= 80

Y= 112/6

By equation 3) 2X + 6*112/6 = 120

X= 4

By equation 2) 8Z = 80 – 8

Z= 9

X<Y>Z

Incorrect

By equation 1) * 2 – 2)

2X + 6Y + 8Z = 96*2

2X + 8Z= 80

Y= 112/6

By equation 3) 2X + 6*112/6 = 120

X= 4

By equation 2) 8Z = 80 – 8

Z= 9

X<Y>Z

Question 8 of 8

8. Question

Find the present age of B

Quantity 1: Three years before the ratio of ages A and B was 4:3. Five years after the ratio will be 8:7.

Quantity 2 : 10 years before the average of the age of A and B was 25. After 5 years the ratio of the age of A and B will be 5:3.

Correct

Q1: 3 yrs before A= 4x B= 3x

4x + 8/ 3x + 8= 8/7

28x + 56= 24x+ 64

X= 2

B= 3*2= 6+3 = 9

Q2: 10 yrs ago the total age was= 25*2=50

Presently total age= 50+10+10= 70

After 5 yrs the age will be 70+5+5= 80

The age of B= 80* 3/8= 30

Quantity 1< Quantity 2

Incorrect

Q1: 3 yrs before A= 4x B= 3x

4x + 8/ 3x + 8= 8/7

28x + 56= 24x+ 64

X= 2

B= 3*2= 6+3 = 9

Q2: 10 yrs ago the total age was= 25*2=50

Presently total age= 50+10+10= 70

After 5 yrs the age will be 70+5+5= 80

The age of B= 80* 3/8= 30

Quantity 1< Quantity 2

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