Hello and welcome to ExamPundit. Here is a set of Data Sufficiency Quiz for SBI PO Mains 2015.
Directions (Q. 1-5):
Each of the questions below consists of a question and two statements (I) and
(II). You have to decide whether the
data provided in the statements are sufficient to answer the question and based on this give answer
Each of the questions below consists of a question and two statements (I) and
(II). You have to decide whether the
data provided in the statements are sufficient to answer the question and based on this give answer
(a) If the data in
statement (I) alone are sufficient to answer the question, while the data in
statement (II) alone are not sufficient.
statement (I) alone are sufficient to answer the question, while the data in
statement (II) alone are not sufficient.
(b) If the data in
statement (II) alone are sufficient to answer the question, while the data in
statement (I) alone are not sufficient.
statement (II) alone are sufficient to answer the question, while the data in
statement (I) alone are not sufficient.
(c) If the data either
in statement (I) alone or in statement (II) alone are sufficient to answer the
question.
in statement (I) alone or in statement (II) alone are sufficient to answer the
question.
(d) If the data given
in both the statements (I) and (II) together are not sufficient to answer the
question.
in both the statements (I) and (II) together are not sufficient to answer the
question.
(e) If the data in both
the statements (I) and (II) together are necessary to answer the question.
the statements (I) and (II) together are necessary to answer the question.
1. What is the
difference between the present ages of A and B if the sum of their present ages
is 70 years?
difference between the present ages of A and B if the sum of their present ages
is 70 years?
I. Five years ago
the age of B was twice the age of A.
the age of B was twice the age of A.
II. After five
years the age of A will be 60% of the age of B.
years the age of A will be 60% of the age of B.
Solutions -Let the present age of A and B be ‘x’ and ‘y’ respectively. x + y = 70… (i)
From (I), (y – 5) = 2(x –5) or 2x – y = 5 … (ii)
From eqn (i) and (ii), x = 25 and y = 45
From (ii), (x + 5) = (y 5) 100 60 +
or, 5x – 3y = – 10 … (iii)
From eqn (i) and (iii), x = 25, y = 45 |
---|
2. What is a
two-digit number?
two-digit number?
I. The difference
between the digits of the two-digit number is 3.
between the digits of the two-digit number is 3.
II. The digit in
the unit’s place is greater than the digit in the ten’s place.
the unit’s place is greater than the digit in the ten’s place.
Solutions -Let the number be 10x + y.
From (II), y > x and from (I), y – x = 3
But to find the value of ‘x’ and ‘y’ we need one more equation. |
---|
3. Among three
integers X, Y and Z, which is the greatest?
integers X, Y and Z, which is the greatest?
I. X is 62.5% of
Z
Z
II. The
difference between X and Y is 30.
difference between X and Y is 30.
Solutions -From (I), X = 62.5/100 ´ Z or X < Z … (1)
From (II), X – Y = 30 or X > Y … (2)
From (1) and (2), Z > X > Y ‘Z’ is the greatest |
---|
4. If X and Y are
integers, then is X + Y an even number?
integers, then is X + Y an even number?
I. X > Y
II. 12 < X
< 14 and 10 < Y < 14
< 14 and 10 < Y < 14
Solutions -From (II), 12 < X < 14
‘X’ can be 13
And 10 < Y < 14, so ‘Y’ can be 11, 12, 13
From (I) X > Y
Y =
11 or 12
When Y = 11 then X + Y = 13 + 11 = 24 (even number).
But when Y = 12 then X + Y = 13 + 12 = 25, which is an odd
number. So, data given is not sufficient |
---|
5. What is the ratio
of the speed of a boat in still water to the speed of the stream?
of the speed of a boat in still water to the speed of the stream?
I. It takes 3
hours to cover a distance downstream.
hours to cover a distance downstream.
II. It takes 5
hours to cover the same distance upstream.
hours to cover the same distance upstream.
Solutions – Let the speed of the boat in still water be ‘x’ and the speed of the stream be ‘y’.
Speed downstream = x + y
And speed upstream = x – y
From (I), distance = 3x(x + y)
And from (II), distance = 5(x – y)
3(x + y) = 5(x – y)
3x + 3y = 5x – 5y
2x = 8y
x/y = 4/1 So, x:y = 4:1 |
---|
Regards
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