Simplifications for IBPS PO 2015 – Set 2

Exampundit.in

7 years ago

Hello and welcome to ExamPundit. Here is a set of Simplifications for IBPS PO 2015.

1. 1/37
x 5106 + 9/23 × 5681= ? × 3

(a) 518 (b) 642 (c) 787 (d) 896 (e) 936

2. 3√12167 + 3√4096 = √?

(a) 1369 (b) 1521 (c) 1681 (d) 1849 (e) 2209

3. 17.76 ÷ 0.37 +
24.32 ÷ 0.38 = ?

(a) 112 (b) 136 (c) 148 (d) 164 (e) 186

4. 0.32% of 1685 +
0.48% of 2145 = ?

(a) 11.264 (b) 12.718 (c) 13.806 (d) 14.208 (e) 15.688

5. 7164 ÷ 59.7 × 7.85
= ?

(a) 648 (b) 712 (c) 884 (d) 942 (e) 1024

6. (4.913)2/3
÷ 2.89 × (8.3521)-1.2 = (1.7)?

(a) 3.2 (b) -4.8 (c) 1.2 (d) -4.2 (e) 2.4

7. (21/34
of √4624) ÷
0.6 = ?

(a) 60 (b) 64 (c) 70 (d) 72 (e) 84

8. 0.78 + ? × 72 =
13.74

(a) 1.2 (b) 0.96 (c) 0.8 (d) 0.24 (e) 0.18

9. [(546)2
÷ 91] ÷
12 = ? ÷ 8

(a) 2104 (b) 2136 (c) 2168 (d) 2184 (e) 2196

10. 3/7
of 5/11 2772 = 30% of ?

(a) 1200 (b) 1500 (c) 1600 (d) 1800 (e) 2100

Solutions:

1. 3 x ? = 5106/37 + 9×5681/23
= 138+2223 = 2361

? = 2361/3 = 787

2. √? = 3√12167 + 3√4096 = 23+16 = 39

? = (39)2 = 1521

3. 17.76/0.37 + 24.32/0.38
= 48+64 = 112

4. ? = 0.32×1685/100 + 0.48×2145/100

= 5.392+10.296 = 15.688

5. ? = 7164/59.7 x 7.85 = 120 x 7.85 =
942

6. (1.73)2/3 ÷ (1.7)2 × (1.74 )–1.2

(1.7)2 ÷ (1.7)2 × (1.7)–4.8
= (1.7)2-2-4.8 = (1.7)-4.8

So, ? = – 4.8

7. (21/34 x 68) ÷ 0.6 = 42 ÷ 0.6 = 70

8. ? × 72 = 13.74 – 0.78 = 12.96

? = 12.96/72 = 0.18

9. ? ÷ 8 = (546 x 546/91) ÷ 12 = 3276
÷ 12 = 273

? = 273 x 8 = 2184

10. 30 x ?/100 = 3 x 5 x 2772/7
x 11 = 540

So, ? = 540×10/3 = 1800

Regards

Team ExamPundit