Hello and welcome to exampundit. Today we are sharing a set of Data Interpretation Quiz on Time and Work and Missing Data for upcoming SBI PO Mains 2018 exam.
The following set of questions contains 2 Hard Level Data Interpretation Quiz with 10 Questions to answer and a total of 10 minutes.
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The following set of quiz is created as per the recent trends and pattern of SBI PO Mains 2018.
Quiz Name: DI for SBI PO Mains
Time: 8 Minutes
Level: Moderate
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Question 1 of 8
1. Question
Laptops Seller Ranveer Seller Deepika CP PROFIT % MP CP PROFIT % MP Dell 25 Lenovo 20 25000 12 HP 28000 Asus 20 Sony 35 16000 30 Study the above table carefully and answer the following questions:
Note:
 i) Some data is missing, you have to calculate that data if it is required to answer the question.
 ii) Selling price may or may not be equal to M.P. Solution
Question: If the ratio between S.P. of Lenovo and M.P. of HP sold by Y is 3 : 4 then what is the average of Cost price of 2 laptops of Lenovo bought by X and 6 laptops of Lenovo bought by Y if X gave 10% discount of M.P.
Correct
Sp of Lenovo by Deepika= 28000 * ¾ = 21000
CP of Lenovo bought by Ranveer= 25000 * 90/100 * 100/120
= 18750
CP of Lenovo bought by Deepika= 21000 * 100/112= 18750
Required average= ( 2 * 18750) + ( 6 * 18750) / 8 = 18750
Incorrect
Sp of Lenovo by Deepika= 28000 * ¾ = 21000
CP of Lenovo bought by Ranveer= 25000 * 90/100 * 100/120
= 18750
CP of Lenovo bought by Deepika= 21000 * 100/112= 18750
Required average= ( 2 * 18750) + ( 6 * 18750) / 8 = 18750

Question 2 of 8
2. Question
Laptops Seller Ranveer Seller Deepika CP PROFIT % MP CP PROFIT % MP Dell 25 Lenovo 20 25000 12 HP 28000 Asus 20 Sony 35 16000 30 Study the above table carefully and answer the following questions:
Note:
 i) Some data is missing, you have to calculate that data if it is required to answer the question.
 ii) Selling price may or may not be equal to M.P. Solution
Question: How much percentage C.P. of Lenovo laptop sold by seller X is less than MP of Sony laptop sold by seller Y. If X gave 10% discount on Lenovo laptop while seller Y gave 20% discount on Sony Laptop on M.P? (Approximately)
Correct
Sp of Lenovo sold by Ranveer= 25000 [ 1 – 10/100]
22500
22500 = [1 + 20/100] * CP
CP= 18750
SP of Sony sold by Deepika= 16000 [ 1 + 30/100 ]
= 20800
MP * [ 1 – 20/100] = 20800
MP= 26000
Required %= (26000 – 18750) / 26000 * 100
= 27.88% ~ 28%
Incorrect
Sp of Lenovo sold by Ranveer= 25000 [ 1 – 10/100]
22500
22500 = [1 + 20/100] * CP
CP= 18750
SP of Sony sold by Deepika= 16000 [ 1 + 30/100 ]
= 20800
MP * [ 1 – 20/100] = 20800
MP= 26000
Required %= (26000 – 18750) / 26000 * 100
= 27.88% ~ 28%

Question 3 of 8
3. Question
Laptops Seller Ranveer Seller Deepika CP PROFIT % MP CP PROFIT % MP Dell 25 Lenovo 20 25000 12 HP 28000 Asus 20 Sony 35 16000 30 Study the above table carefully and answer the following questions:
Note:
 i) Some data is missing, you have to calculate that data if it is required to answer the question.
 ii) Selling price may or may not be equal to M.P. Solution
Question: How much percentage C.P. of Lenovo laptop sold by seller X is less than MP of Sony laptop sold by seller Y. If X gave 10% discount on Lenovo laptop while seller Y gave 20% discount on Sony Laptop on M.P? (Approximately)
Correct
Cp of Asus= X
Cp of Sony= Y
X + Y/ 2= 14000
X +Y = 28000………….. 1)
X * 1.2 + Y * 1.35/2 = 18000
1.2X + 1.35Y= 36000………..2)
By solving both equations:
X= 12000
Y= 16000
Required difference= 16000 – 12000
= 4000
Incorrect
Cp of Asus= X
Cp of Sony= Y
X + Y/ 2= 14000
X +Y = 28000………….. 1)
X * 1.2 + Y * 1.35/2 = 18000
1.2X + 1.35Y= 36000………..2)
By solving both equations:
X= 12000
Y= 16000
Required difference= 16000 – 12000
= 4000

Question 4 of 8
4. Question
Study the following table carefully to answer the given questions:
Files Number No. of days for which individuals worked on different files Part of files uncompleted after all work M N O P 1 6 6 2 3 1/3 2 3 4 3 4 5 3 2 1/6 5 2 2 3 5 1/12 Question: M and N started working on Files 1. They completed 1/3rd of work after which they left and O joined the Files. O can complete the whole Files in 12 days. After O worked for his assigned number of days, P joined the files and worked for his assigned number of days. Find the number of days in which P can complete the whole Files 1?
Correct
M and N complete 1/3rd, O completed 1/12 * 2 = 1/6
Completed work before P joined is 1/3 + 1/6 = 1/2
P = 1 – 1/2 = 1/2 of work
Now Files uncompleted after P left = 1/3
So P did = 1/2 – 1/3 = 1/6 of work
He worked for 3 days, means he complete 1/6th of work in 3 days.
He can do complete Files 1 in 6/1 * 3 = 18 days
Incorrect
M and N complete 1/3rd, O completed 1/12 * 2 = 1/6
Completed work before P joined is 1/3 + 1/6 = 1/2
P = 1 – 1/2 = 1/2 of work
Now Files uncompleted after P left = 1/3
So P did = 1/2 – 1/3 = 1/6 of work
He worked for 3 days, means he complete 1/6th of work in 3 days.
He can do complete Files 1 in 6/1 * 3 = 18 days

Question 5 of 8
5. Question
Study the following table carefully to answer the given questions:
Files Number No. of days for which individuals worked on different files Part of files uncompleted after all work M N O P 1 6 6 2 3 1/3 2 3 4 3 4 5 3 2 1/6 5 2 2 3 5 1/12 Question: M who can complete Files 2 in 20 days, worked for 6 days. The ratio of number of days in which N and O can complete Files 2 alone is 5: 8. P could not come to work for Files 2. Find the number of days in which N and O can complete 13/30 of Files 2 together, given that if P who can complete work in 12 days had also joined the Files for 4 days, the Files would have been completed in
Correct
Number of days in which N and O can complete Files 2 alone is 5x and 8x respectively.
Now if P also joined for 4 days, Files would have been completed, means
6/20 + 3/5x + 4/8x + 4/12 = 1
11/10x = 11/30
x = 3
So N can complete Files in 5x = 15 days, and C in 8x = 24 days.
So 13/30 work, N and O together – (1/15 + 1/24)*y = 13/30
y = 4 days
Incorrect
Number of days in which N and O can complete Files 2 alone is 5x and 8x respectively.
Now if P also joined for 4 days, Files would have been completed, means
6/20 + 3/5x + 4/8x + 4/12 = 1
11/10x = 11/30
x = 3
So N can complete Files in 5x = 15 days, and C in 8x = 24 days.
So 13/30 work, N and O together – (1/15 + 1/24)*y = 13/30
y = 4 days

Question 6 of 8
6. Question
Study the following table carefully to answer the given questions:
Files Number No. of days for which individuals worked on different files Part of files uncompleted after all work M N O P 1 6 6 2 3 1/3 2 3 4 3 4 5 3 2 1/6 5 2 2 3 5 1/12 Question: A file 3 was to be completed in 6 days. To complete Files in time, all M, N, O and P decided to work in pairs in alternate days. M and O on 1st day, N and P on 2nd day, M and O on 3rd, and so on. But they could not complete Files in time. What percent of Files 3 remain uncompleted if M, N, O and P can complete whole Files 3 in 12, 18, 20 and 15 days respectively?
Correct
Files is to be completed in 6 days. They all worked in pairs on alternate means all worked for 3 days each.
On 1st day, work completed by M and O = 1/12 + 1/20 = 2/15
On 2nd day, work completed by N and P = 1/18 + 1/15 = 11/90
1st pair worked for 3 days, so work completed by them = 2/15 * 3 = 2/5
Similarly, by N and P = 11/90 * 3 = 11/30
So part of Files uncompleted= 1 – (2/5 + 11/30) = 7/30
So % = 7/30 * 100 = 70/3%
Incorrect
Files is to be completed in 6 days. They all worked in pairs on alternate means all worked for 3 days each.
On 1st day, work completed by M and O = 1/12 + 1/20 = 2/15
On 2nd day, work completed by N and P = 1/18 + 1/15 = 11/90
1st pair worked for 3 days, so work completed by them = 2/15 * 3 = 2/5
Similarly, by N and P = 11/90 * 3 = 11/30
So part of Files uncompleted= 1 – (2/5 + 11/30) = 7/30
So % = 7/30 * 100 = 70/3%

Question 7 of 8
7. Question
Study the following table carefully to answer the given questions:
Files Number No. of days for which individuals worked on different files Part of files uncompleted after all work M N O P 1 6 6 2 3 1/3 2 3 4 3 4 5 3 2 1/6 5 2 2 3 5 1/12 Question: N and O can complete the whole Files 4 in 6 days working together. M is 20% more efficient than O and 40% less efficient that N. How many days did P work on Files 4 if P can complete whole Files 4 in 18 days?
Correct
Efficiency — M : O = 120 : 100 = 6 : 5
So days ratio = 5 : 6
Similarly, M : N = 60 : 100 = 3 : 5, so days 5 : 3
N/M = 3/5, M/O = 5/6
So ratio of days for N : M : O is 3 : 5 : 6 …………(1)
Now — N and O can complete the whole Files 4 in 6 days working together, and ratio of no. of days in which they can complete work alone is N and O from (1) is 3 : 6 = 1 : 2
So
1/x + 1/2x = 1/6
x = 9
So N can complete work in 9 days, O in 18 days and then M in 15 days
Now, let P worked for ‘y’ days on Files 4. So
1/15 *5 + 1/9 * 3 + 1/18 * 2 + 1/18 * y = 1 – 1/6
y = 1 day
Incorrect
Efficiency — M : O = 120 : 100 = 6 : 5
So days ratio = 5 : 6
Similarly, M : N = 60 : 100 = 3 : 5, so days 5 : 3
N/M = 3/5, M/O = 5/6
So ratio of days for N : M : O is 3 : 5 : 6 …………(1)
Now — N and O can complete the whole Files 4 in 6 days working together, and ratio of no. of days in which they can complete work alone is N and O from (1) is 3 : 6 = 1 : 2
So
1/x + 1/2x = 1/6
x = 9
So N can complete work in 9 days, O in 18 days and then M in 15 days
Now, let P worked for ‘y’ days on Files 4. So
1/15 *5 + 1/9 * 3 + 1/18 * 2 + 1/18 * y = 1 – 1/6
y = 1 day

Question 8 of 8
8. Question
Study the following table carefully to answer the given questions:
Files Number No. of days for which individuals worked on different files Part of files uncompleted after all work M N O P 1 6 6 2 3 1/3 2 3 4 3 4 5 3 2 1/6 5 2 2 3 5 1/12 Question: M, Q and P worked on Files numbered 5.N and O alone can complete whole Files numbered 5 in 20 and 30 days respectively. Q who is 3/2 times efficient than N and O together replaces both of them and worked for same number of days for which N and O had to work. M completed 1/12th of the work. Find in how many days all M, N, O, and P can complete the Files 5 together.
Correct
N and O together can complete work in 12 days [1/20 + 1/30 = 5/60 — 12 days]
Efficiency E: (N+O) = 3/2 : 1 = 3 : 2
So, ratio of number days = 2: 3
So Q can complete whole work in 2/3 * 12= 8 days
Now Q worked for (2+3) = 5 days – total days for which N and O worked.
So Q completed 5/8 of work, M completed 1/12 of work. 1/12 is uncompleted work. Let x is no. of days in Which P can complete whole work. So
M’s work + Q’s work + P’s work = 1 – uncompleted work
1/12 + 5/8 + 5/x = 1 – 1/12
Solve, x = 24 = no. of days in which P can alone complete Files 5.
A completed 1/12th work in 2 days, so he can complete whole Files in 2*12 = 24 days
M = 24, N = 20, O = 30, P = 24
So, together they can complete in = 1/24 + 1/20 + 1/30 + 1/24 = 1/6 = 6 days
Incorrect
N and O together can complete work in 12 days [1/20 + 1/30 = 5/60 — 12 days]
Efficiency E: (N+O) = 3/2 : 1 = 3 : 2
So, ratio of number days = 2: 3
So Q can complete whole work in 2/3 * 12= 8 days
Now Q worked for (2+3) = 5 days – total days for which N and O worked.
So Q completed 5/8 of work, M completed 1/12 of work. 1/12 is uncompleted work. Let x is no. of days in Which P can complete whole work. So
M’s work + Q’s work + P’s work = 1 – uncompleted work
1/12 + 5/8 + 5/x = 1 – 1/12
Solve, x = 24 = no. of days in which P can alone complete Files 5.
A completed 1/12th work in 2 days, so he can complete whole Files in 2*12 = 24 days
M = 24, N = 20, O = 30, P = 24
So, together they can complete in = 1/24 + 1/20 + 1/30 + 1/24 = 1/6 = 6 days
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