Hello and welcome to exampundit. Today we are sharing a set of Data Interpretation Quiz on Boats and Streams and Missing Data for upcoming SBI PO Mains 2018 exam.
The following set of questions contains 2 Hard Level Data Interpretation Quiz with 10 Questions to answer and a total of 10 minutes.
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The following set of quiz is created as per the recent trends and pattern of SBI PO Mains 2018.
Quiz Name: DI for SBI PO Mains
Time: 10 Minutes
Level: Moderate
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Question 1 of 10
1. Question
Field Name Shape Side (mm) Base ( mm) Height (m) Radius (m) Cost of flooring ( Rs. Per square m) Cost of fencing ( Rs per m) A Triangle – 16 12 – 50 20 B Rectangle 10 * 20 ( Length * Breadth) – – – 30 15 C Square 15 – – – 40 18 D Parallelogram – 20 12 – 60 25 E Circle – – – 10 45 22 Question: What is the cost of flooring of A?
Correct
A is triangle
Area of A=1/2(16X12)=96m^2
Cost of flooring of A=96X50=4800
Incorrect
A is triangle
Area of A=1/2(16X12)=96m^2
Cost of flooring of A=96X50=4800

Question 2 of 10
2. Question
Field Name Shape Side (mm) Base ( mm) Height (m) Radius (m) Cost of flooring ( Rs. Per square m) Cost of fencing ( Rs per m) A Triangle – 16 12 – 50 20 B Rectangle 10 * 20 ( Length * Breadth) – – – 30 15 C Square 15 – – – 40 18 D Parallelogram – 20 12 – 60 25 E Circle – – – 10 45 22 Question: What is the difference between the cost of fencing of C and that of B?
Correct
Perimeter of B=2(10+20)=60 m
Cost of fencing of B=60X15=900 Rs.
Perimeter of C=4X15=60 m
So, cost of fencing of C=60X18=1080 Rs.
Required difference=1080900=180
Incorrect
Perimeter of B=2(10+20)=60 m
Cost of fencing of B=60X15=900 Rs.
Perimeter of C=4X15=60 m
So, cost of fencing of C=60X18=1080 Rs.
Required difference=1080900=180

Question 3 of 10
3. Question
Field Name Shape Side (mm) Base ( mm) Height (m) Radius (m) Cost of flooring ( Rs. Per square m) Cost of fencing ( Rs per m) A Triangle – 16 12 – 50 20 B Rectangle 10 * 20 ( Length * Breadth) – – – 30 15 C Square 15 – – – 40 18 D Parallelogram – 20 12 – 60 25 E Circle – – – 10 45 22 Question: What is the ratio of the cost of flooring to that of fencing of field D?
Correct
Area of D=Base X Height
=20 X 12
=240 m^2
Cost of flooring of D
=240 X 60
=14400
Perimeter of D
=2(20+12)
=64
Cost of Fencing of D
=64 X 25
=1600
Required ratio
=14400:1600 =9:1
Incorrect
Area of D=Base X Height
=20 X 12
=240 m^2
Cost of flooring of D
=240 X 60
=14400
Perimeter of D
=2(20+12)
=64
Cost of Fencing of D
=64 X 25
=1600
Required ratio
=14400:1600 =9:1

Question 4 of 10
4. Question
Field Name Shape Side (mm) Base ( mm) Height (m) Radius (m) Cost of flooring ( Rs. Per square m) Cost of fencing ( Rs per m) A Triangle – 16 12 – 50 20 B Rectangle 10 * 20 ( Length * Breadth) – – – 30 15 C Square 15 – – – 40 18 D Parallelogram – 20 12 – 60 25 E Circle – – – 10 45 22 Question: The cost of fencing of field E is approximately what per cent of the cost of flooring of field C?
Correct
Perimeter of E
=2PiR=2 X 22/7 X 10
=440/7 m
Cost of Fencing of E
=440/7 X 22
=1382.85
Area of C
=15^2
=225 m^2
Cost of flooring of C
=225X40
=9000
Required % =1382.85 X 100/9000 =15.36%
Incorrect
Perimeter of E
=2PiR=2 X 22/7 X 10
=440/7 m
Cost of Fencing of E
=440/7 X 22
=1382.85
Area of C
=15^2
=225 m^2
Cost of flooring of C
=225X40
=9000
Required % =1382.85 X 100/9000 =15.36%

Question 5 of 10
5. Question
Field Name Shape Side (mm) Base ( mm) Height (m) Radius (m) Cost of flooring ( Rs. Per square m) Cost of fencing ( Rs per m) A Triangle – 16 12 – 50 20 B Rectangle 10 * 20 ( Length * Breadth) – – – 30 15 C Square 15 – – – 40 18 D Parallelogram – 20 12 – 60 25 E Circle – – – 10 45 22 Question: The cost of fencing of field C is what per cent of the cost of fencing of field D?
Correct
Fencing cost of C =1080
Fencing cost of D =1600
Required %=( 1080X100)/1600 =67.5%
Incorrect
Fencing cost of C =1080
Fencing cost of D =1600
Required %=( 1080X100)/1600 =67.5%

Question 6 of 10
6. Question
Study the following pie chart and table carefully and answer the questions carefully:
Day Speed in Still Water ( km/hr) Sunday 2 Monday – Tuesday 3 Wednesday – Thursday 3.5 Friday 2.5 Saturday – Question: On Tuesday the boat takes a total of 5 hrs to cover the both upstream and downstream distance. Ratio of speed of stream going in upstream to downstream is 4 : 5. If the time required to cross the distance in downstream is 5 hr, Find the downstream speed.
Correct
Downstream speed= 5x Upstream= 4x
On Tuesday, Upstream Distance= 150*18/100= 27 km
Downstream Distance= 200*20/100= 40 km
3 + Stream= 5x 3 – Stream= 4 x
Stream= 5x – 3 Stream= 3 4x
40 / 5x – 3= 5
X= 1
Downstream speed= 5*1= 5 km/hr
Incorrect
Downstream speed= 5x Upstream= 4x
On Tuesday, Upstream Distance= 150*18/100= 27 km
Downstream Distance= 200*20/100= 40 km
3 + Stream= 5x 3 – Stream= 4 x
Stream= 5x – 3 Stream= 3 4x
40 / 5x – 3= 5
X= 1
Downstream speed= 5*1= 5 km/hr

Question 7 of 10
7. Question
Study the following pie chart and table carefully and answer the questions carefully:
Day Speed in Still Water ( km/hr) Sunday 2 Monday – Tuesday 3 Wednesday – Thursday 3.5 Friday 2.5 Saturday – Question: Time taken to cover the upstream distance on Thursday is same as time taken to cover downstream distance on Friday. Total speed of stream on Thursday and Friday is 15km/hr. Find the speed of stream on Friday.
Correct
Upstream distance on Thursday= 150*16/100= 24
Upstream distance on Friday= 150 * 22/100= 33
Downstream distance on Thursday= 200 * 15/100=30
Downstream distance on Friday= 200 * 15/100= 30
Let speed of stream upstream on Friday = x
, then speed of stream on Thursday = 15 – x
On Thursday upstream distance= 3.5 15 + x = x – 11.5Friday downstream distance= 2.5+ x
24/ x – 11.5 = 30/ 2.5 + x
60 + 24x= 30x – 345
6x = 405
X= 67.5
Incorrect
Upstream distance on Thursday= 150*16/100= 24
Upstream distance on Friday= 150 * 22/100= 33
Downstream distance on Thursday= 200 * 15/100=30
Downstream distance on Friday= 200 * 15/100= 30
Let speed of stream upstream on Friday = x
, then speed of stream on Thursday = 15 – x
On Thursday upstream distance= 3.5 15 + x = x – 11.5Friday downstream distance= 2.5+ x
24/ x – 11.5 = 30/ 2.5 + x
60 + 24x= 30x – 345
6x = 405
X= 67.5

Question 8 of 10
8. Question
Study the following pie chart and table carefully and answer the questions carefully:
Day Speed in Still Water ( km/hr) Sunday 2 Monday – Tuesday 3 Wednesday – Thursday 3.5 Friday 2.5 Saturday – Question: On Wednesday, Ratio of speed of boat in stream in going upstream to downstream is 3 : 5. The difference between time to cover upstream distance and downstream distance is 5 hours; find the difference between speed of boat in stream in going upstream to downstream. The speed of boat in still water on Wednesday is the average speed of stream on Sunday and Friday.
Correct
On Wednesday the speed of boat in still water = (2.5 + 2) / 2= 2.25 km/hr
Speed in boat in stream in going Upstream= 3x Speed in boat in stream in going Downstream= 5x
Downstream distance= 200*16/100= 32 km Upstream distance= 150* 25/100= 37.5 km
Downstream speed= 2.25 + 5x Upstream speed= 2.25 – 3x
@ 32/(2.25 + 5x) – 37.5/(2.25 – 3x) = 10
Answer= 2.3674 = 2.37
So required difference :5*2.37 – 3* 2.37 = 11.85 – 7.11= 4.74
Incorrect
On Wednesday the speed of boat in still water = (2.5 + 2) / 2= 2.25 km/hr
Speed in boat in stream in going Upstream= 3x Speed in boat in stream in going Downstream= 5x
Downstream distance= 200*16/100= 32 km Upstream distance= 150* 25/100= 37.5 km
Downstream speed= 2.25 + 5x Upstream speed= 2.25 – 3x
@ 32/(2.25 + 5x) – 37.5/(2.25 – 3x) = 10
Answer= 2.3674 = 2.37
So required difference :5*2.37 – 3* 2.37 = 11.85 – 7.11= 4.74

Question 9 of 10
9. Question
Study the following pie chart and table carefully and answer the questions carefully:
Day Speed in Still Water ( km/hr) Sunday 2 Monday – Tuesday 3 Wednesday – Thursday 3.5 Friday 2.5 Saturday – Question: Time taken to cover the upstream distance on Thursday is 12 hours more than time taken to cover the downstream distance on Friday. Total speed of boat on stream on Thursday and Friday is 10 km/hr. Find the ratio of speed of boat on stream on Thursday and Friday.
Correct
Let speed of boat on stream on upstream on Thursday = x, then speed of boat on stream on downstream on Friday = (10x)
Distance covered the upstream distance on Thursday=150* 16/100= 24 km
Distance covered the downstream distance on Friday= 200* 15/100= 30 km
Upstream speed on Thursday= 3.5 – x
Downstream speed on Friday= 2.5 + ( 10x)
@ [30 / 2.5 + ( 10x)] – [ 24/ 3.5 – x]= 12
x = 8
Thursday= 8Friday= 108 = 2
Required ratio= 8 : 2
= 4: 1
Incorrect
Let speed of boat on stream on upstream on Thursday = x, then speed of boat on stream on downstream on Friday = (10x)
Distance covered the upstream distance on Thursday=150* 16/100= 24 km
Distance covered the downstream distance on Friday= 200* 15/100= 30 km
Upstream speed on Thursday= 3.5 – x
Downstream speed on Friday= 2.5 + ( 10x)
@ [30 / 2.5 + ( 10x)] – [ 24/ 3.5 – x]= 12
x = 8
Thursday= 8Friday= 108 = 2
Required ratio= 8 : 2
= 4: 1

Question 10 of 10
10. Question
Study the following pie chart and table carefully and answer the questions carefully:
Day Speed in Still Water ( km/hr) Sunday 2 Monday – Tuesday 3 Wednesday – Thursday 3.5 Friday 2.5 Saturday – Question: On Monday, Ratio of speed of boat on stream in going upstream to downstream is 4 : 6. Also difference in speed of boat on stream in going upstream and downstream is 10 km/hr. If the total time taken by boat to cover upstream and downstream distance is 10 hours on Monday, find the speed of boat in still water.
Correct
Speed of boat on stream in going upstream= 4x
Speed of boat on stream in going downstream= 6x
6x – 4x= 10
X= 5
Speed of boat on stream in going upstream= 4*5= 20
Speed of boat on stream in going downstream= 6*5= 30
On Monday distance covered on downstream=200* 22/100= 44 km
Distance covered on upstream= 150* 20/100= 30 km
speed of boat in still water= x
So for Monday
@ 44/ ( x + 30) + 30/ ( x – 20) = 10x= 23.27
Incorrect
Speed of boat on stream in going upstream= 4x
Speed of boat on stream in going downstream= 6x
6x – 4x= 10
X= 5
Speed of boat on stream in going upstream= 4*5= 20
Speed of boat on stream in going downstream= 6*5= 30
On Monday distance covered on downstream=200* 22/100= 44 km
Distance covered on upstream= 150* 20/100= 30 km
speed of boat in still water= x
So for Monday
@ 44/ ( x + 30) + 30/ ( x – 20) = 10x= 23.27
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