SBI PO Mains 2017: New Coding Decoding Problems in Reasoning – Set 6

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5 years ago

Hello and welcome to exampundit. Here is a set of New Pattern Coding Decoding for SBI PO Mains 2017.

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Given below is a set of sentences along
with their codes in a specific machine language.

Watched pot never boils –
4&g 13$u 11#w 25$v

Beggars cannot choose – 24%w 24%h
25&v

Familiarity breeds contempt – 25%v
24*w 21+b

Counsel is no command – 24&o
18@v 24&g 13@r

According to the above coding pattern,
answer the following questions:

1. What will be the code for “ bemuzzle
fuzzed” ?

a) 21%g
25*h

b) 21*g
25%h

c) 20%r
16&t

d) Either a or b

e) None

2. ”ace” will be coded as?

a) 20%t

b) 3&t

c) 26#h

d) 26*t

e) None

3. ”muzzling as crazy” will be coded as?

a) 14*j
24$b 26@v

b) 24@j
14&b 20&t

c) 3&t
17+y 25&r

d) Either b or c

e) None

4. What will be the code for “ scuzzy
quick” ?

a) 10&t
18&e

b) 10&n 17%r

c) 8%b
10$n

d) Either b or c

e) None

5. ”17$b” will be the code for?

a) Jamie

b) Jammy

c) Yummy

d) Tommy

e) Fanny

Answers:

Ans-a
Ans-c
Ans-a
Ans-c
Ans-b

Solution-

Every code consists of three parts- a
number (either 1 or 2 digit) , a symbol and a letter of English alphabet.

The number in the code is the reverse
numeric value of the first letter of the word

For example 4=w, 11=p, 13=n.

The symbol is coded with respect to the
number of digits in the word.

By comparing the common terms of codes and
eliminating we get the following :

2=@

3=#

5=$

6=%

7=&

8=*

11=+

The letter in the code is the alphabet two
places to left of the last letter of the word.

For example in the word never, r is the
last letter hence the last part of the code will be r+2=u

Hence the words and their codes are:

Watched
pot never boils

4&g 11#w 13$u
25$v

Beggars cannot choose

25&v 24%w 24%h

Familiarity breeds contempt

21+b 25%v 24*w

Counsel is no
command

24&o 18@v
13@r 24&g

For previous 5 sets – Click here

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