Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz for SBI PO 2018 Prelims exam with Timer. The following set consists Miscellaneous problems.
10 Questions on Miscellaneous Problems, 10 Minutes total time.
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The following questions are created as per the recent trends and level of SBI PO Prelims 2018.
Test Name: Quantitative Aptitude Quiz for SBI PO Prelims 2018
Duration: 10 min
Level: Moderate
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Question 1 of 10
1. Question
A person lent Rs. 2500 each to two of his friends. What is the rate of interest? To get the answer which of following information is sufficient?
A. Amount repaid by one of them was Rs. 2700.
B. The other one repaid Rs. 2900 after the due period.
C. Amount was given to one of them on simple interest and to another on compound interest.Correct
No time is mentioned so the answer can’t be determined.
Incorrect
No time is mentioned so the answer can’t be determined.

Question 2 of 10
2. Question
A boat sails 13 km upstream in 4 hrs. What is the speed of the stream? To get the answer this of the following information is/are sufficient.
A. The boat goes downstream in 2 hrs.
B. The boat sails 6 km/hr in still water.Correct
Speed in upstream= 13/4= 3.25 km/hr
From A we can’t get proper information.
From B we can get Speed in still water= 6 km/hr
Upstream= Still water speed – Speed of stream
3.25 = 6 – X
X= 6 – 3.25 = 2.75 km/hr
Incorrect
Speed in upstream= 13/4= 3.25 km/hr
From A we can’t get proper information.
From B we can get Speed in still water= 6 km/hr
Upstream= Still water speed – Speed of stream
3.25 = 6 – X
X= 6 – 3.25 = 2.75 km/hr

Question 3 of 10
3. Question
A goods train X crosses another train Y in 28 sec. To find the length of Y which of the following statements is/are sufficient?
A. Speed of X is 45 km/hr.
B. Length of X is 130 m .
C. Speed of Y is 54 km/hr.Correct
We can’t find out the length of another train. We find out the length of train X. The answer can’t be determined.
Incorrect
We can’t find out the length of another train. We find out the length of train X. The answer can’t be determined.

Question 4 of 10
4. Question
A trader sells a homogeneous mixture of A and B at the rate of Rs. 17 per kg. To find the profit percentage of the trader, which of the following statements is/are sufficient?
A. He bought A at the rate of Rs. 20 per kg.
B. He bought B at the rate of Rs. 13 per kg.Correct
Data are insufficient.
Incorrect
Data are insufficient.

Question 5 of 10
5. Question
In a quadrilateral the length of one of its diagonal is 23cm and the perpendiculars drawn on this diagonal from other two vertices measure 17 cm and 7 cm respectively. Find the area of the quadrilateral.
Correct
Area= ½ * any diagonal * (sum of perpendiculars drawn on diagonal from two vertices)
= ½ * 23 * ( 17 + 7) = 276 sq m
Incorrect
Area= ½ * any diagonal * (sum of perpendiculars drawn on diagonal from two vertices)
= ½ * 23 * ( 17 + 7) = 276 sq m

Question 6 of 10
6. Question
If the heights of two cones are in the ratio 1: 4 and their diameters are in the ratio 4:5. What is the ratio of their volumes?
Correct
Volume= 1/3 * π ( radius)² ( height)
Volume of first cone/ Volume of second cone
= 1/3 π ( radius of first cone)² ( height) / 1/3 π ( radius of second cone)² ( height)
Ratio of volume= (Ratio of radii)² ( ratio of height)
= ( 4: 5 )² ( 1: 4)
= 16/25 * ¼ = 4: 25
Incorrect
Volume= 1/3 * π ( radius)² ( height)
Volume of first cone/ Volume of second cone
= 1/3 π ( radius of first cone)² ( height) / 1/3 π ( radius of second cone)² ( height)
Ratio of volume= (Ratio of radii)² ( ratio of height)
= ( 4: 5 )² ( 1: 4)
= 16/25 * ¼ = 4: 25

Question 7 of 10
7. Question
Find the area of a triangle whose sides are 50 meters, 78 meters, 112 meters respectively and also find the perpendicular from the opposite angle on the side 112 meter.
Correct
S= ½ (50 + 78 + 112) meters
= ½ * 240 meters = 120 meters
(S – 50) = 120 – 50= 70 meters
(S – 78)= 120 – 78= 42 meters
(S 112) = 120 – 112 = 8 meters
Area= √ (120 * 70 * 42 * 8) sq m
= 1680 sq m
Perpendicular= 2 area/ Base = 1680 * 2 / 112 = 30 meter
Incorrect
S= ½ (50 + 78 + 112) meters
= ½ * 240 meters = 120 meters
(S – 50) = 120 – 50= 70 meters
(S – 78)= 120 – 78= 42 meters
(S 112) = 120 – 112 = 8 meters
Area= √ (120 * 70 * 42 * 8) sq m
= 1680 sq m
Perpendicular= 2 area/ Base = 1680 * 2 / 112 = 30 meter

Question 8 of 10
8. Question
A room is 7 meters long and 5 meters broad. The doors and windows occupy 5 sq. meters and the cost of papering the remaing part of the surface of the walls with paper 75 cm wide at Rs. 4.20 per piece of 13 m is Rs, 39.20. Find the height of the room.
Correct
Length of the paper= rs. 39.20/ Rs. 4.20 * 13 m
= 364/3 m
Area of the paper= 364/3 * 75/100 = 91 sq m
Area of the walls= 91 + 5 = 96 sq. m.
Now, area of walls= 2 (7 + 5) * height = (24 * height) sq. m
24 * height = 96
Height= 96 / 24 = 4 meters
Incorrect
Length of the paper= rs. 39.20/ Rs. 4.20 * 13 m
= 364/3 m
Area of the paper= 364/3 * 75/100 = 91 sq m
Area of the walls= 91 + 5 = 96 sq. m.
Now, area of walls= 2 (7 + 5) * height = (24 * height) sq. m
24 * height = 96
Height= 96 / 24 = 4 meters

Question 9 of 10
9. Question
The area of a rhombus is 1152 m². To find out its side which of the following is/are necessary?
A. One of its diagonal is 36 m.
B. The other diagonal is 32 m.
C. All the four sides are equal.Correct
Area of rhombus= Product of diagonal
With the help of either A or B we can get the other diagonals. Now we have both the diagonals. Which provide us the length of side.
Incorrect
Area of rhombus= Product of diagonal
With the help of either A or B we can get the other diagonals. Now we have both the diagonals. Which provide us the length of side.

Question 10 of 10
10. Question
The walls of a room are to be mounted with wall paper 36 inches wide. To find out the length of paper, which of the following information is/are sufficient?
A. The height of the room is 14 ft.
B. The total area of doors and windows is 56 sq. ft.
C. The perimeter of the room is 28 ft.Correct
All are necessary.
Incorrect
All are necessary.
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