SBI PO 2018: Quantitative Aptitude Quiz for Prelims – 10

Hello and welcome to exampundit. Here is a set of Quantitative Aptitude Quiz for SBI PO 2018 Prelims exam with Timer. The following set consists Miscellaneous problems.

8 Questions on Miscellaneous Problems, 8 Minutes total time.

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The following questions are created as per the recent trends and level of SBI PO Prelims 2018.

Test Name: Misecllaneous for SBI PO Prelims 2018

Duration: 8 min

Level: Moderate

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Question 1 of 8

1. Question

Three circles of equal radii touch each other as shown in the figure given below. The radius of each circle is 2 cm. What is the area of the shaded region?

Correct

Area of the triangle= √3/4 * 4² = 4√3

Area of 3 circles enclosed by the triangle= 3*π* 2²* 60/360 = 2π

Area of the shaded region= 4√3 – 2π = 2 (2√3 – π) cm²

Incorrect

Area of the triangle= √3/4 * 4² = 4√3

Area of 3 circles enclosed by the triangle= 3*π* 2²* 60/360 = 2π

Area of the shaded region= 4√3 – 2π = 2 (2√3 – π) cm²

Question 2 of 8

2. Question

The ratio of the cost price to the marked price of an article is 2:3 and the ratio of the percentage profit to the percentage discount is 3:2. What is the discount percentage?

Correct

Ratio of CP: MP= 2x: 3x

Profit= x

The ratio of % profit: % discount= 3:2

Cp= 200 SP= 300

3x/100*200 + 2x/100* 300= 100

6x + 6x= 100

X= 100/12= 25/3%

Incorrect

Ratio of CP: MP= 2x: 3x

Profit= x

The ratio of % profit: % discount= 3:2

Cp= 200 SP= 300

3x/100*200 + 2x/100* 300= 100

6x + 6x= 100

X= 100/12= 25/3%

Question 3 of 8

3. Question

Babul borrowed Rs. 1200 at 12% rate of interest. He repaid Rs. 500 at the end of the first year. What is the amount required to pay at the end of the second year to discharge his loan which was calculated at compound interest?

Correct

Amount to be paid at the end of 2 years= 1200*12*2/100 + 1200= 1488

Amount left as principal for the second year= 1488-500= 988

Amount to be paid after 2nd year= 988+ 988*12/100= 1106.56

Incorrect

Amount to be paid at the end of 2 years= 1200*12*2/100 + 1200= 1488

Amount left as principal for the second year= 1488-500= 988

Amount to be paid after 2nd year= 988+ 988*12/100= 1106.56

Question 4 of 8

4. Question

A book consists of 40 pages, 30 lines on each page and 50 characters on each line. If this content is written in another note book consisting of 30 lines per page and 20 characters per line then the required no. of pages will be how much % more than the previous no. of pages?

Correct

40* 30* 50 = x * 30 * 20

X= 100

% increase in the no. of pages= 100-40/40 * 100 = 150%

Incorrect

40* 30* 50 = x * 30 * 20

X= 100

% increase in the no. of pages= 100-40/40 * 100 = 150%

Question 5 of 8

5. Question

Sourav wants to purchase Lenovo mobile phone. The shopkeepers told him to pay 25% tax if he asked for the bill. Sourav managed to get a discount of 5% on the actual sale price (without tax) of the mobile and paid to the shopkeeper Rs. 5000. In doing so, he managed to avoid paying the 25% tax. What is the amount of discount that he has received on the selling price (inclusive tax)?

Correct

Sp= 100 Sp= 125 (with tax)

New SP = 100- 5 = 95

Effective discount= 125-95 = 30

When SP is 95 then discount is 30

When SP is 5000, discount will be= 30/95 * 5000=1578.95

Incorrect

Sp= 100 Sp= 125 (with tax)

New SP = 100- 5 = 95

Effective discount= 125-95 = 30

When SP is 95 then discount is 30

When SP is 5000, discount will be= 30/95 * 5000=1578.95

Question 6 of 8

6. Question

Suhani is thrice as efficient as Raima and Raima can do a piece of work in 27 days. Raima started working and after a few days Suhani joined him. They completed the work in 15 days from the beginning. For how many days did they work together?

Correct

Efficiency of Suhani= 3x Raima= x

Raima can do a work in 27 days

Suhani can do a work= 27/3= 9 days

In one day they both work in= 1/27 + 1/9= 4/27

Suhani joined Raima after (15-x) days

15-x/27 + 4x/27 = 1

15 – x + 4x= 27

3x= 12

X= 4

Incorrect

Efficiency of Suhani= 3x Raima= x

Raima can do a work in 27 days

Suhani can do a work= 27/3= 9 days

In one day they both work in= 1/27 + 1/9= 4/27

Suhani joined Raima after (15-x) days

15-x/27 + 4x/27 = 1

15 – x + 4x= 27

3x= 12

X= 4

Question 7 of 8

7. Question

When Rahul Increases his speed from 25 kmph to 30 kmph he takes 2 hr less than his usual time to cover a certain distance. What is the distance covered by Rahul in the usual time?

Correct

25t = 30 (t – 2)

25t = 30t – 60

T= 12

Distance= 25*12= 300

Incorrect

25t = 30 (t – 2)

25t = 30t – 60

T= 12

Distance= 25*12= 300

Question 8 of 8

8. Question

From a group of 5 men and 2 women, 2 persons are selected randomly. Find the probability that at least one woman is selected.