# Reasoning Quiz for Upcoming IBPS Exams – Set 21 | Puzzle – Mains

Hello and welcome to exampundit. Here is a set of Puzzle Quiz for Upcoming IBPS Bank Exams. The following set of questions are moderate mains level.
Eight friends namely – Ami,
Rahul, Atul, Saroj, Pritz, Deepak, Mika and Prem of an educational institute
are sitting around a circular table. The number of people facing away from the
center is equal to the number of people facing the center. Each friend likes
different colour i.e. Green, Pink, White, Black, Brown, Red, Blue and Yellow.
Red and White colours are of same brand. These are the further information-
Mika is fourth to the right of
the one, who likes brown. Deepak and Rahul are the males. Deepak likes black
and facing the center, sits opposite to the one who likes yellow. The person
who likes brown is facing the center. Rahul likes Green and sits second to the
right of Atul and both are facing outside. Mika is an immediate neighbour of
Deepak. The one who likes Pink is also the person whose name starts with the
same letter as his favorite colour and is facing the center, he is also to the
immediate right of Mika. To the immediate left of Pritz is Prem, who is facing
outside and is opposite to Ami, who likes white and faces the center. No two
people of the same gender sit next to each other. Pritz and Atul are the
males.  Only two males face the center.
Friends who like colours of same brand are sitting opposite each other.
Q.1 who among the following likes
Blue?
(a) Saroj
(b) Pritz
(c) Mika
(d) Cannot be determined
(e) None of these.
Q.2 who among the following faces
the center?
(a) Saroj
(b) Mika
(c) Prem
(d) One who likes yellow
(e) None of these.
Q.3 who sits opposite to the Saroj?
(a) Pritz
(b) Mika
(c) Deepak
(d) Cannot be determined
(e) None of these.

Q.4 who among the following sits
opposite to the one who likes Pink?
(a) Red
(b) Blue
(c) Green
(d) White
(e) None of these.
Q.5 Find the odd one out?
(a) Pritz – Blue
(b) Ami – Green
(c) Saroj – Yellow
(d) Rahul – White
(e) Mika – Black

1. C
2. A
3. B
4. C
5. E

Solution:

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