Reasoning Quiz for IBPS Clerk Prelims 2015 – Set 8



Hello and welcome to ExamPundit. Here is a set of Reasoning Quiz for IBPS Clerk Prelims 2015.

Directions
(Q. 1-5): Study the following arrangement of numbers, letters and symbols carefully
and
answer the questions given
below:
R @ 2 9 T V A Y 5 © # J 1 P 8 Q $ E 3 ★ H % 6 W 4
I d U Z
1. Four of
the following five are alike in a certain way based on their positions in the
above arrangement
and so
form a group. Which is the one That does not belong to that group?
1) J P ©
2) E Q ★
3) W I %
4) 9 V @
5) 1 # 5

Solutions –
2. Which
of the following is the fifth to the right of the nineteenth element from the
right end?
1) J 2) V 3) W 4) 8 5) None of these

Solutions – 5th to the right of the 19th element from the right end means (19 – 5 =) 14th from the light
end, ie, Q.
3. How
many such numbers are there in the above arrangement, each of which is
immediately preceded
by a
consonant and immediately followed by a symbol ?
1) One 2) Two 3) Three 4) Four 5) More than four

Solutions – We have to look for consonant-number-symbol combination. There is only one such
combination, which is y 5 ©.
4. If the
positions of the last eighteen elements in the above arrangement are reversed,
which of the
following will be the
seventeenth from the left end ?
1) H 2) P 3) W 4) 6 5) None of these

Solutions – There are 29 elements in all in the given arrangement. If the positions of the last 18
elements are reversed, then the positions of the first 11 elements from the left end would be
not changed, Now, 17 – 11 = 6, ie required answer would be the 6th element from the right
in original sequence.
 6th from the right end = W
5. How
many such vowels are there in the above arrangement, each of which is either immediately
followed by a symbol or immediately
preceded by a symbol ?
1) None 2) One 3) Two 4) Three 5) Four

Solutions –  We have to look for vowel-symbol and symbol-vowel conbinations. Such conbinations
are $ E and Id.
Directions
(Q. 6-10): In the following questions, the symbols ©,
d, $, and % are
used with the
following meaning as
illustrated below:
(i) ‘A d B’ means
‘A is not greater than B’
(ii) ‘A% B’ means ‘A is not smaller than B’.
(iii) ‘A © B’ means ‘A is neither greater than nor smaller than
B’.
(iv) ‘A $ B’ means ‘A is greater than B’.
(v) ‘A ★ B’ means ‘A is smaller than B’.
Now in
each of the following questions assuming the given statements to be true, find
which of the two
conclusions
I and II given below them is/are definitely true ?
Give answer (1) if only Conclusion I is true.
Give answer (2) if only Conclusion II is true.
Give answer (3) if either Conclusion I or II is true.
Give answer (4) if neither Conclusion I nor II is true.
Give answer (5) if both Conclusions I and II are true.
6. Statements: R $ J, J
% M, M © K
Conclusions:
I.
K © J        II.K ★ J

Solutions – R > J.. (i); J ≥ M… (ii) M = K … (iii)
Combining (ii) and (iii), we get J ≥ M = K ⇒ J ≥ K. Conclusions I and II together are exhaustive. Hence, either I or II is true
7. Statements: D d R, M $ R, M © F
Conclusions:
I.
F $ D         II.F $ R

Solutions –  D ≤ R… (i); M > R…(ii); M = F… (iii)
Combining all, we get, D ≤ R < M = F ⇒ D < F  ⇒ F > D. Hence conclusion I is true. Again, from (ii) and (iii), we get R < M = F ⇒ R < F ⇒ F > R. Therefore conclusion II is also true.
8. Statements: H © F, F
$ R, R ★ K
Conclusions:
I.
R ★ H      II.K $ F

Solutions – H = F … (i); F > R … (ii); R < K … (iii)
From (i) and (ii), H = F > R ⇒ R < H. Hence conclusion I is true. Again, form (ii) and (iii),
F > R < K ⇒ No relationship between K and F can be determined. Therefore conclusion II
is not true.
9. Statements: B % D, D ★ T, T d R
Conclusions:
I.
B $ T         II.R $ D

Solutions – B ≥ D… (i); D < T … (ii); T ≤ R… (iii)
From (i) and (ii), B ≥ D < T ⇒ No relationship between B and T can be determined. Therefore
conclusion I is not true.
From (ii) and (iii), D < T ≤ R ⇒ D < R ⇒ R > D. Hence conclusion II is true.
10. Statements: M % N,
N ★ A, A $ B
Conclusions:
I.
B ★ N      II.A $ M

Solutions –  M ≥ N… (i); N < A… (ii); A > B …(iii)
From (ii) and (iii), N < A > B ⇒ No relationship between N and B can be determined. Hence
conclusion I is not true. Again, from (i) and (ii), M ≥ N < A.⇒No relationship between M
and A can be determined. Therefore conclusion II is also not true.



Regards

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This post was last modified on November 27, 2017 8:59 am