Quantitative Aptitude Quiz for SBI PO Prelims 2015 – Set 4

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6 years ago

Hello and welcome to ExamPundit. Here is a set of quantitative aptitude quiz for SBI PO Prelims 2015.

1. In an examination,
44% of students failed in subject A and 36% of the students failed in subject B
and 18% failed in both the subjects. If 352 students passed in only one
subject, then how many failed in both the subjects?

(a) 126

(b) 144

(d) 158

(e) None of these

2. A shopkeeper
allows two successive discounts of 10% and 5% on the marked price of an article
but charges a sales tax of 5% on the discounted price. If a customer pays Rs.
718.2 as including the sales tax, then what is the marked price?

(a) 750

(b) 780

(d) 830

(e) None of these

3. Arun is 33 1/3
% as efficient as Ravi. Mandar does 40% of the work done by Arun and Ravi
together. If Mandar alone does the work in 60 days, in how many days Ravi and Mandar
together can finish the same work?

(a) 20 2/3 day

(b) 25 4/5 day

(d) 20 20/23 day

(e) None of these

4. The ratio of
present ages of A and C is 7 : 9 and present age of B is equal to the average
ages of A and C after 2 years. If the ratio of present age of B and age of C after
four years is 6 : 7 then what will be the ratio of age of A after four years to
that of present age of B?

(a) 13 : 14

(b) 14 : 13

(d) 7 : 6

(e) None of these

5. In a two-digit
numbers the digit in the unit’s place is less than twice the digit in ten’s
place by 1 and the difference between the number obtained by interchanging its
digit and the original number is half the number by adding 7 to original
number. Then the sum of its digit is.

(a) 11

(b) 9

(d) 13

(e) None of these

6. 7 litres are drawn
from a beaker full of spirit then filled with water. The operation is performed
2 more times. The ratio of quantity of spirit now left in the beaker to that of
water is 27 : 37. How much spirit did the beaker hold in original?

(a) 32 litres

(b) 28 litres

(d) 26 litres

(e) None of these

7. A certain amount
of money gets four times to its original amount after 24 years at a simple
interest. What will be the interest on a sum of Rs.8500 compounded annually at
the same rate of interest after 2 year?

(a) Rs. 2220.5

(b) Rs. 2150.75

(d) Rs. 2257.6

(e) None of these

8. A square of area
64 m2 is formed from a wire of certain length. If a rectangle is
formed from the same wire, what will be its length, if length is 66 2/3%
more than the width?

(a) 10 metre

(b) 12 metre

(d) 8.5 metre

(e) None of these

9. A shopkeeper mixes
of 24 kg of sugar worth Rs. 35 per kg with another quality of sugar of Rs.42
per kg. By selling the mixture at Rs. 41.04 per kg, he may gain 8%. How much
sugar of second quality has been added to the mixture?

(a) 18 kg

(b) 32 kg

(d) 28 kg

(e) None of these

10. A man can row 11 2/3
kmph in still water and finds that it takes six times more to row up than to
row down the same distance in the
river. What is the speed of the current?

(a) 7 2/3kmph

(b) 5 1/3kmph

(d) 8 1/3kmph

(e) None of these

Solutions:

1. TOTAL NO. OF STUDENTS PASSED IN BOTH SUBJECTS= 100-
(44+36-18) = 38

TOTAL PASSED IN SUBJECT A = 56

TOTAL PASSED SUBJECT B= 64

PASSED ONLY A = 56-38= 18

PASSED ONLY B= 64-38=26

SO 18+26= 44 = PASSED IN ONLY ONE SUBJECT

44% = 352

=> 18% = 352/44 *18 = 144

2. Total discount, –10 –5 + 10 x 5/100

= 14.5%

SP+SP x 5/100 = 718.2

so, 105/100 x SP = 718.2

So, Selling Price = 684

3. Mandar ka ek din ka kaam arun aur ravi k ek din k kaam ka
40% h

then

1/60 = 40/100 * AR/(A+R)

here R is no . of days required by R to do work

similarly A.

now A is 1/3 efficient of R. Then no. of days required by A
will be 3 times of R

putting A=3R in above equation

we can get R=32

Now Mandar and Ravi will do complete work in 60*32/(60+32)

hence D option is correct.

4. Let the ages of A and C be 7x and 9x

B = 7x + 2 + 9x + 2 / 2 = 8x + 2

Given, 8x + 2 / 9x + 4 = 6 /7

So x = 5

So, A = 35

B = 42

C = 45

So…35+4/42 = 39/42 = 13:14

5. Let the unit digit be y and ten digit be x

Then,

y = 2 x – 1 …………. (I)

Difference = 10 y + x – (10 x + y)

= 9 y – 9x

Now, 9 (y – x) = 10x + y + 7 / 2

or, 17 y – 28 x = 7 …………………………….. (II)

Solving (I) & (II) x = 4, y = 7

Number = 47

Sum = 4 + 7 = 11

6. spirit left/water left= 27/37

spirit left/(spirit left +water)=27/(37+27)=27/64

As the operation is performed 3 times ,

then (total spirit-7/total spirit)^3= 27/64= (3/4)^3
=3/4=4-1/4

so initially spirit=4*7=28

7. 300% increase in = 24 years

In one year = 300/24

= 12.5%

So Rate of interest = 12.5

CI= (8500(1+25/2*100)/2-1)

So CI = 2257.6

8. Area of the square = 64 m2

Side = 8

Length of the wire = 8×4 = 32

Perimeter of the rectangle = 32

Let Length be b. Then, 2(a + b) = 32 and breadth – a

So, a + b = 16

Now,

or, a + 5/3a = 16

8a/3 = 16

a = 6

So Length = 5/3 x 6 = 10mt.

9. Actual price of the mixture = 41.04/1.08 = 38

So, 4:3

Amount of sugar of second quality added = 24*3/4 = 18

10. Let the distance be d

Speed of the current = x km/ph

d/35/3-x = 6d/35/3+x

or, 70-6x =35/3+x

or, 7x = 175/3

so x = 25/3 = 8 1/3 kmh

Some of the explanations have been given by our members
Spider, Optimus and Priyanka.

Regards

Team ExamPundit