Hello and welcome to exampundit. Here is a set of Quant Quiz on Percentage.

Q:1- Three-fourth of one-fifth of four-seventh of a number is 20. What is 30% of that number.

- 70
- 75
- 80
- 85
- 90

Answer

**Option:**Â A

**Explanation:**

Let the number be x.

Â Â Then, Â Â Â Â Â Â Â Â Â Â Â Â 3/4 of 1/5 of 4/7 of x = 20

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X = (20 Ã— 7 Ã— 5)/3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 700/3

Â So 30% of 700/3 Â Â = 30*700/100*3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 70.

Q:2- The sum of two numbers is 3630. If 5.5% of one number is equal to 9.5% of the other,

Then the numbers are:

- 2199,1221
- 2299,1331
- 2399,1441
- 2288,1551
- 2199,1661

Answer

**Option:**Â B

**Explanation:**

Let the numbers be x and y.

Â Â Then Â Â Â Â Â Â Â Â Â Â Â 5.5% of x Â = Â 9.5% of y

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 11X =19y

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Y = 11x/19

Â Â Â Â Now given, Â Â Â Â Â Â Â Â x+y = 3630

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X + 11x/19 = 3630

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X(one number) = 2299

Â Â Â Â Â Â And, y(another number) = 1331. Â

Q:3- From the salary of an Engineer, 20% is deducted as house rent , 10% on the rest, he spends on conveyance, 10% of the rest he pay as electricity bill and 10% of the rest, he spends on clothes. Then he is left with Rs.51840. Find his total salary.

- 80,000
- 85,000
- 90,000
- 95,000
- 100,000

Answer

**Option:**Â E

**Explanation:**

Let the total salary be Rs. X.

Â Â Then Â Â Â xÃ—80Ã—90Ã—90Ã—80/100Ã—100Ã—100Ã—100 Â = 51840

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X = Â 51840Ã—10000/64Ã—81

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X = 100,000.

Q:4- Rahul gave 50% of the amount he had to Deepak. Deepak in turn gave one-fifth of what he received from Rahul to Sumit. After paying Rs.400 to the auto driver out of the amount he got from Deepak, Sumit now has Rs.800 left with him. How much amount did Rahul have ?

- 10,000
- 11,000
- 12,000
- 13,000
- 14,000

Answer

**Option:**Â C

**Explanation:**

Let the Â amount with Rahul be Rs.x.

Â Â Then, Â amount received by Sumit = 1/5 of 50% of Rs. X.

So Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10% of x =400 + 800

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10% of x = 1200

Then , Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x = 12000.

Q:5- 270 sweets were distributed equally among children in such a way that the number of sweets received by each child is 30% of the total number of children. How many sweets did each child received ?

- 3
- 6
- 9
- 10
- 12

Answer

**Option:**Â C

**Explanation:**

Let the number of total children be x.

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Then, x(30% 0f x) = 270

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X2 Â = Â (270 Ã— 10)/3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X = 30

So, Â Â number of sweets received by each child = 30% of 30

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 9.

Q:6- In an examination of n questions, a student replied 20 out of the first 30 questions correctly. Of the remaining questions, he answered half of them correctly. All the questions have the same credit. If the student gets 60% marks, the value of n is :

- 50
- 60
- 70
- 80
- 90

Answer

**Option:**Â A

**Explanation:**

20 + (n-30) Ã—1/2 = 60% of n

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Then Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â n = 50. Â

Q:7-40% of the student in an exam were girls, 80% of the boys and 75% of the girls passed and 360 girls failed. The number of boys failed was :

- 431
- 432
- 433
- 333
- 444

Answer

**Option:**Â B

**Explanation:**

Let the total number of student be x.

Â Â Â Â Â Then, Â Â Â Â Â Â Â Â Â Â (100-75)% of 40% of x = 360

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X Â = 3600

Â Number of boys failed Â = Â (100-80)% of (100-40)% of 3600

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 432.

Q:8- 5/9 part of the population in a village are males. If 30% of the males are married , the % of unmarried females in the total population is :

- 25%
- 26%
- (250/9)%
- 28%
- 29%

Answer

**Option:**Â C

**Explanation:**

Let total population = x

Â Then, Â number of males Â Â = 5x/9

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Married males = 30% of 5x/9

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = x/6

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Married females = x/6

Total number of females= 4x/9

Â Â Â Â Â Â Â Â Unmarried females = 5x/18

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Required % = (250/9)%

Q:9- The population of a city increase by 10% annually. If its population in 2007 was 13,31000. Â What it was in 2004 ?

- 1000000
- 1100000
- 1200000
- 1300000
- 1400000

Answer

**Option:**Â A

**Explanation:**

Population in 2004 =1331000/(1+10/100)3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =Rs.1000000.

Q:10- The value of a machine depreciates at the rate of 5% every year. It was purchased 3 years ago. If its present value is Rs.685900, Its purchase price was :

- 770,000
- 780,000
- 790,000
- 800,000
- 810,000

Answer

**Option:**Â D

**Explanation:**

Purchase price Â =Rs. [685900/(1-5/100)3]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = Rs.800,000.

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