# Quant Quiz – Percentage – 11

Hello and welcome to exampundit. Here is a set of Quantitative Aptitude quiz on Percentage problems. Q:1-Deepak’s annual income is Rs. 8,40,000.He spends 20% of his monthly income on house rent, 30% on household items and 20% on transport. If he invests two-third of the remaining amount in mutual funds, what is the amount left with him every month?
(a) 6900
(b) 6950
(c) 7000
(d) 7050
(e) 7100

Answer

Option: C
Explanation:

Deepak’s monthly income= 840000/12

= 70000 / month

He spends,      20% (HR)+30%(HI)+20%(Tr.) =70% of his monthly income

Remaining amount of income = 30% of 70000

= 21000

He invest Two-third of remaining income,

= 2/3×21000

= 14000

Amount left every month       = 21000-14000

=7000.

Q:2-The price of a T.V. set is decreased by 20% as a result of which the sale increased by 25%.what will be the effect on the total revenue of the shop?
(a) No effect
(b) 5% increase
(c) 5% decrease
(d) 10% increase
(e) 10% decrease

Answer

Option: A
Explanation:

Let original price per T.V.= 100

Original sale  = 100 T.V.

Then      total revenue   =  Rs.(100×100)

=  10,000

New revenue = (80×125)

=  10,000

So,      ans would be No effect.

Q:3-Mr.Vikas a businessman had the income in the year 2015, such that he earned a profit of 25% on his investment in the business. In the year 2016,his investment was less by Rs.10000 but still had the same as that in 2015.thus, the present profit earned in 2016 increased by 10%. What was his investment in 2015?
(a) 240000
(b) 250000
(c) 260000
(d) 270000
(e) 280000

Answer

Option: C
Explanation:

Let his investment in the year 2015 = x

Then, income in 2015    = Rs.[x+25% of x]

= Rs.125x/100

Income in 2016            = [(x-10000)130/100 ]

125x/100  =  (x-10000)130/100

X = 260,000.

Q:4- In a fraction, if numerator is increased by 35% and denominator is increased by 80%, then what fraction of the original is the new fraction ?
(a) 3/2
(b) 4/3
(c) 3/4
(d) 2/3
(e) none

Answer

Option: C
Explanation:

Let the original fraction be x/y.

Then, new fraction    = 135% of x/180% of y

= 3x/4y

New fraction/original fraction= 3x/4y × y/x

= 3/4 .

Q:5- A student who got 25% marks fails by 10 mark marks but another student who gets 35% marks get 20 marks more than the passing marks. Find maximum and passing marks?
(a) 250, 85
(b) 300, 50
(c) 300, 85
(d) 300,100
(e) 300, 120

Answer

Option: C
Explanation:

passing mark equal for both the student.

So           25%of marks + 10  = 35% of marks – 20

10% = 30

So                                  100%= 300

Maximum marks  = 300

Passing marks  =  25% of 300 + 10

= 85 marks.

Q:6- A student has to obtain 33% of the total marks to pass. He got 200 marks and failed by 31 marks. The maximum marks are:
(a) 700
(b) 710
(c) 720
(d) 730
(e) 740

Answer

Option: A
Explanation:

Passing marks    = 33%

So            200 + 31  = 33%

1% = 7

100%= 700

Maximum marks   = 700.

Q:7- A salesman is allowed 4% discount on the total sales made by him plus a bonus of 1% on the sales over Rs.10,000.If his total earnings were Rs.2000,then his total sales were:
(a) 40000
(b) 41000
(c) 42000
(d) 43000
(e) 44000

Answer

Option: C
Explanation:

Let the total sales be Rs. X.

Then 4% of x + 1% of (x-10000) = 2000

4x/100 + (x-10000)/100  = 2000

5x  =  200000 + 10000

X = 42000.

Q:8- In a recent survey, 40% of house contained two or more people. Of those houses containing only one person, 25% were having only a male. What is the percentage of all houses, which contain exactly one female and no males?
(a) 30%
(b) 35%
(c) 40%
(d) 45%
(e) None

Answer

Option: D
Explanation:

Let the total number of houses be x.

Then, Number of houses having one female only= (100-25)% of (100-40)% of x

= (75/100 × 60/100 × x )

= 9x/20

Required percentage = (9x/20 × 1/x × 100)%

= 45%.

Q:9- The present population of a state estimated to be 16 crores is expected to increase to 25 crores during the next two years. The uniform rate of growth is:
(a) 22%
(b) 23%
(c) 24%
(d) 25%
(e) 26%

Answer

Option: D
Explanation:

16 crores × ( 1+R/100)2 = 25 crores

(1+R/100)2 = 25/16

1 + R/100 = 5/4

R = 25%.

Q:10- In a company, the ratio of total number of female and total number of male employees is 6:11. The company has only two branches –one is in Noida and another is in Gurugram. If the total number of female employees in Noida branch is 480,which is 40% of the total female employees in the company, what is total number of male employees in the company?
(a) 2100
(b) 2200
(c) 2300
(d) 2400
(e) 2500

Answer

Option: B
Explanation:

Ratio of Female and Male = 6:11

Female in Gurugram   = 480  (which is 40% of total female)

40%  = 480

Then  total Female in company = 1200

6’s Ratio  = 1200

Then                           1’s = 200

So total number of male employees is,

11’s =  11 × 200

= 2200.

Regards

Team EP