Hello and welcome to exampundit. Today we are sharing an Quantitative Aptitude Quiz for IBPS PO 2018 Prelims Exam.

The following set consists 10 questions on Ratio and Proportion Questions with 10 minutes in hand.

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The following set of quiz is created as per the standards of upcoming IBPS PO Prelims exam 2018.

Quiz Name: Quantitative Aptitude Quiz for IBPS PO Prelims 2018

Time: 10 Minutes

Difficulty Level: Moderate

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Question 1 of 10

1. Question

The ratio of marks obtained by P & Q is 8:7. If the combined average of their percentage is 52.5 and their sum of marks is 525, find the maximum marks for the exam.

Correct

Solution : P:Q = 8:7

So, their individual marks : P= 8/15 * 525 = 280

Q= 7/15 * 525 = 245

Let the maximum marks is x.

(280/x*100) + (245/x*100) / 2 = 52.5

=> x = 500.

Incorrect

Solution : P:Q = 8:7

So, their individual marks : P= 8/15 * 525 = 280

Q= 7/15 * 525 = 245

Let the maximum marks is x.

(280/x*100) + (245/x*100) / 2 = 52.5

=> x = 500.

Question 2 of 10

2. Question

Rs. 558 is divided among three brothers Sanju, Birju, Makhon such that 12 times Sanju’s share is equal to 6 times Birju’s share which is equal to 8 times Makhon’s share. How much Sanju got?

The monthly salaries of two persons in the ratio 8:9. If each receives an increase of Rs. 20 in the salary, the ratio becomes 25:28. Find their salaries.

Correct

Solution:

(8x + 20) / (9x + 20) = 25/28

=> x = 60

8x= 8 * 60 = 480 & 9x= 9 * 60 = 540

Incorrect

Solution:

(8x + 20) / (9x + 20) = 25/28

=> x = 60

8x= 8 * 60 = 480 & 9x= 9 * 60 = 540

Question 4 of 10

4. Question

The ratio of incomes of A and B is 7:3 and ratio of their expenditures is 9:4. If B saves one-fifth of his income, find their ratio of savings.

Correct

Incorrect

Question 5 of 10

5. Question

Some apples are to be distributed among some boys. If two more apples are available, each boy gets six apples. If five less apples are available, each boy gets five apples. How many apples are available?

Correct

Solution: suppose no. of apples = x

So, no. of students – (x+2)/6 = (x-5)/5; => x=40

Incorrect

Solution: suppose no. of apples = x

So, no. of students – (x+2)/6 = (x-5)/5; => x=40

Question 6 of 10

6. Question

625 ml of a mixture contains milk and water in the ratio 3:2. How much more water is to be added to get a new mixture containing milk and water in the ratio 5:4 ?

Correct

Solution: Quantity of milk = ⅗ * 625 = 375 ml Quantity of water = ⅖ * 625 = 250 ml Let ‘x’ be the quantity that should be added to make the ratio 5:4

According the question;

375/ 250+x = 5/4

=> x= 50

Incorrect

Solution: Quantity of milk = ⅗ * 625 = 375 ml Quantity of water = ⅖ * 625 = 250 ml Let ‘x’ be the quantity that should be added to make the ratio 5:4

According the question;

375/ 250+x = 5/4

=> x= 50

Question 7 of 10

7. Question

Age of P is fourteen times that of Q. After 6 years, P is eight times elder to Q. What is the present age of Q?

Correct

Solution: Let the age of P and Q are x years and y years respectively. Then, (x + 6) = 8(y + 6) ; => 14y + 6 = 8y + 48 ; => 6y = 42; => y = 7. The present age of Q= 7 years

Incorrect

Solution: Let the age of P and Q are x years and y years respectively. Then, (x + 6) = 8(y + 6) ; => 14y + 6 = 8y + 48 ; => 6y = 42; => y = 7. The present age of Q= 7 years

Question 8 of 10

8. Question

Pure milk costs Rs. 65 per litre. After adding water the milkman sells the mixture at the rate of Rs. 50 per litre, thereby making a profit of 25%. In what ratio does he mix the two?

Correct

Mean cost price = 100/125 * 50 = 40/- per litre

By the rule of alligation CP of 1 L milk CP of 1 L water

The required ratio = 40:25 = 8:5

Incorrect

Mean cost price = 100/125 * 50 = 40/- per litre

By the rule of alligation CP of 1 L milk CP of 1 L water

The required ratio = 40:25 = 8:5

Question 9 of 10

9. Question

The ages of A and B are in the ratio of 4:9 respectively. After 9 years the ratio of their ages will be 1:2, what is the difference in their ages?

Correct

Solution: Let the present ages of A & B be 4x and 9x years respectively. After 9 years,

(4x+9) / (9x+9) = ½

=>x= 9

Difference = 9x-4x= 5x = 5*9 = 45 years.

Incorrect

Solution: Let the present ages of A & B be 4x and 9x years respectively. After 9 years,

(4x+9) / (9x+9) = ½

=>x= 9

Difference = 9x-4x= 5x = 5*9 = 45 years.

Question 10 of 10

10. Question

Divide Rs. 2850 into three parts, such that first part be double that of second part and second part be ⅓ of the third part.Find the Third part amount?

Correct

First: Second: Third = 2:1:3. Third part = 3 * 2850/6 = 1425

Incorrect

First: Second: Third = 2:1:3. Third part = 3 * 2850/6 = 1425

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