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Today we are giving Popup Quiz on Data Interpretation and Data Analysis.
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The following Set of Data Interpretation & Analysis is for IBPS Clerk & RBI Assistant Mains examinations.
Total Time: 15 minutes
No. of Questions: 15
Level: Moderate
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Question 1 of 15
1. Question
[Directions: Set of 5 Questions] The table shows the financial performances of ten companies for a particular year
NP = Net Profits
NW = Net Worth
GP = Gross Profits
TA = Total Assets
N Sales = Net Sales
Question: If NP/NW ratio is considered to be an index of performance, then which of the companies is the best performer?
Correct
Explanation: The ratio NP/NW is highest for Bajaj Auto, so it is the best performer.
Incorrect
Explanation: The ratio NP/NW is highest for Bajaj Auto, so it is the best performer.

Question 2 of 15
2. Question
[Directions: Set of 5 Questions] The table shows the financial performances of ten companies for a particular year
NP = Net Profits
NW = Net Worth
GP = Gross Profits
TA = Total Assets
N Sales = Net Sales
Question:Highest profit on sales has been achieved by
Correct
Explanation: From the column of net profits of the companies, we can easily conclude that RIL has the highest profit
Incorrect
Explanation: From the column of net profits of the companies, we can easily conclude that RIL has the highest profit

Question 3 of 15
3. Question
[Directions: Set of 5 Questions] The table shows the financial performances of ten companies for a particular year
NP = Net Profits
NW = Net Worth
GP = Gross Profits
TA = Total Assets
N Sales = Net Sales
Question: If executive compensation is a foundation of only net profit on sales, then which organisations could be expected to be most remunerative for an executive?
Correct
Explanation: You don’t need to check net profit on sales for all the companies. B taking a sharp view of the table, you will get that only for two companies:
RIL = 576301/564327 = 1.021
And, Bajaj Auto = 546678/401517 = 1.361
So, Bajaj Auto is your answerIncorrect
Explanation: You don’t need to check net profit on sales for all the companies. B taking a sharp view of the table, you will get that only for two companies:
RIL = 576301/564327 = 1.021
And, Bajaj Auto = 546678/401517 = 1.361
So, Bajaj Auto is your answer 
Question 4 of 15
4. Question
[Directions: Set of 5 Questions] The table shows the financial performances of ten companies for a particular year
NP = Net Profits
NW = Net Worth
GP = Gross Profits
TA = Total Assets
N Sales = Net Sales
Question: If returns on investment is a function of only net profit over net worth, then which company should a person invest in?
Correct
Explanation: From the table. It is clear that net profit over net worth is maximum for Bajaj Auto. So, a person should invest in Bajaj Auto
Incorrect
Explanation: From the table. It is clear that net profit over net worth is maximum for Bajaj Auto. So, a person should invest in Bajaj Auto

Question 5 of 15
5. Question
[Directions: Set of 5 Questions] The table shows the financial performances of ten companies for a particular year
NP = Net Profits
NW = Net Worth
GP = Gross Profits
TA = Total Assets
N Sales = Net Sales
Question: Which one of the groups could be termed as lean as thin (in the context of Total Assets) as well as performing better in terms of profits as compared to Bajaj Auto?
Correct
Explanation: B taking a sharp view of the given table, you will find that Hero Honda satisfied both the conditions
Incorrect
Explanation: B taking a sharp view of the given table, you will find that Hero Honda satisfied both the conditions

Question 6 of 15
6. Question
[Directions: Set of 5 Questions] Study the following bar chart carefully and answer the given questions
The total of the first three deficit countries (in $ million) = $3594.3. The total of the next five deficit countries (in $ million) = $2588.5. The total of the last five deficit countries (in $ million) – $334.2. The total of the four surplus countries (in $ million) = $1860.4
Question: The country whose surplus is nearly equal to the average of the 4 surplus countries is
Correct
Explanation: Total of four surplus = 1860.4
Average of four surplus = 1860.4/4 = 465.1 (near to surplus of USA)Incorrect
Explanation: Total of four surplus = 1860.4
Average of four surplus = 1860.4/4 = 465.1 (near to surplus of USA) 
Question 7 of 15
7. Question
[Directions: Set of 5 Questions] Study the following bar chart carefully and answer the given questions
The total of the first three deficit countries (in $ million) = $3594.3. The total of the next five deficit countries (in $ million) = $2588.5. The total of the last five deficit countries (in $ million) – $334.2. The total of the four surplus countries (in $ million) = $1860.4
Question: The ratio of the deficit of the last five deficit countries to the overall deficit of all the deficit countries is nearly equal to
Correct
Explanation: Total deficit of last five countries = 334.2
Overall deficit of all the deficit countries = 3594.3 + 2588.5 + 334.2 = 6517
Required ratio = 334.2:6517 = 0.0513Incorrect
Explanation: Total deficit of last five countries = 334.2
Overall deficit of all the deficit countries = 3594.3 + 2588.5 + 334.2 = 6517
Required ratio = 334.2:6517 = 0.0513 
Question 8 of 15
8. Question
[Directions: Set of 5 Questions] Study the following bar chart carefully and answer the given questions
The total of the first three deficit countries (in $ million) = $3594.3. The total of the next five deficit countries (in $ million) = $2588.5. The total of the last five deficit countries (in $ million) – $334.2. The total of the four surplus countries (in $ million) = $1860.4
Question: The average of the total deficit of the middle five deficit countries is nearly the deficit of which country?
Correct
Explanation: Total of middle five deficit countries = 2588.5
Average of middle five deficit countries = 2588.5/5 = 517.7 (near to deficit of India)Incorrect
Explanation: Total of middle five deficit countries = 2588.5
Average of middle five deficit countries = 2588.5/5 = 517.7 (near to deficit of India) 
Question 9 of 15
9. Question
[Directions: Set of 5 Questions] Study the following bar chart carefully and answer the given questions
The total of the first three deficit countries (in $ million) = $3594.3. The total of the next five deficit countries (in $ million) = $2588.5. The total of the last five deficit countries (in $ million) – $334.2. The total of the four surplus countries (in $ million) = $1860.4
Question: The ratio of net deficit to net surplus is equal to
Correct
Explanation: Net deficit = 6517
Net surplus = 1860.4
Required ratio = 6517:1860.4Incorrect
Explanation: Net deficit = 6517
Net surplus = 1860.4
Required ratio = 6517:1860.4 
Question 10 of 15
10. Question
[Directions: Set of 5 Questions] Study the following bar chart carefully and answer the given questions
The total of the first three deficit countries (in $ million) = $3594.3. The total of the next five deficit countries (in $ million) = $2588.5. The total of the last five deficit countries (in $ million) – $334.2. The total of the four surplus countries (in $ million) = $1860.4
Question: The ratio of the difference between the highest and the lowest of the surplus countries to the difference between the deficit of Bangladesh and Oman is
Correct
Explanation: Difference between the highest and the lowest of the surplus countries = 665 – 305.7 = 359.3
Difference between the deficit of Bangladesh and Oman = 1225 – 1131.3 = 93.7
Required ratio = 3593:937Incorrect
Explanation: Difference between the highest and the lowest of the surplus countries = 665 – 305.7 = 359.3
Difference between the deficit of Bangladesh and Oman = 1225 – 1131.3 = 93.7
Required ratio = 3593:937 
Question 11 of 15
11. Question
[Directions: Set of 5 Questions] Study the following information carefully and answer the given questions:
For an examination consisting of three subjectsMaths, Physics and Chemistry, 280 students appeared. When the results were declared, 185 students had passed in Maths, 210 had passed in Physics and 222 had passed in Chemistry. All those except 5 students who passed in Maths, passed in Physics. All those except 10 students who passed in Maths, passed in Chemistry. 47 students failed in all the three subjects. 200 students who passed in Physics also passed in Chemistry.
Question: How many students passed in Chemistry only ?
Correct
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18Incorrect
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18 
Question 12 of 15
12. Question
[Directions: Set of 5 Questions] Study the following information carefully and answer the given questions:
For an examination consisting of three subjectsMaths, Physics and Chemistry, 280 students appeared. When the results were declared, 185 students had passed in Maths, 210 had passed in Physics and 222 had passed in Chemistry. All those except 5 students who passed in Maths, passed in Physics. All those except 10 students who passed in Maths, passed in Chemistry. 47 students failed in all the three subjects. 200 students who passed in Physics also passed in Chemistry.
Question: How many students passed in all the three subjects ?
Correct
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18Incorrect
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18 
Question 13 of 15
13. Question
[Directions: Set of 5 Questions] Study the following information carefully and answer the given questions:
For an examination consisting of three subjectsMaths, Physics and Chemistry, 280 students appeared. When the results were declared, 185 students had passed in Maths, 210 had passed in Physics and 222 had passed in Chemistry. All those except 5 students who passed in Maths, passed in Physics. All those except 10 students who passed in Maths, passed in Chemistry. 47 students failed in all the three subjects. 200 students who passed in Physics also passed in Chemistry.
Question: How many students failed in Physics and Maths ?
Correct
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18Incorrect
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18 
Question 14 of 15
14. Question
[Directions: Set of 5 Questions] Study the following information carefully and answer the given questions:
For an examination consisting of three subjectsMaths, Physics and Chemistry, 280 students appeared. When the results were declared, 185 students had passed in Maths, 210 had passed in Physics and 222 had passed in Chemistry. All those except 5 students who passed in Maths, passed in Physics. All those except 10 students who passed in Maths, passed in Chemistry. 47 students failed in all the three subjects. 200 students who passed in Physics also passed in Chemistry.
Question: How many students passed in Maths but failed in both Physics and Chemistry ?
Correct
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18Incorrect
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18 
Question 15 of 15
15. Question
[Directions: Set of 5 Questions] Study the following information carefully and answer the given questions:
For an examination consisting of three subjectsMaths, Physics and Chemistry, 280 students appeared. When the results were declared, 185 students had passed in Maths, 210 had passed in Physics and 222 had passed in Chemistry. All those except 5 students who passed in Maths, passed in Physics. All those except 10 students who passed in Maths, passed in Chemistry. 47 students failed in all the three subjects. 200 students who passed in Physics also passed in Chemistry.
Question: A student has to pass in at least two subjects to get promoted. How many students get promoted ?
Correct
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18Incorrect
Explanation:
Total Number of students = 280
NUmber of students who passed Maths = 185
Number of students who passed Physics = 210
Number of students who passed Chemistry = 222
Students who passed in Maths and physics = 180
Students who passed in Maths and Chemistry = 175
Students who passed in Physics and Chemistry =
200
Number of students who passed in atleast one subject = 280 – 47 = 233
x + w = 180 ….(i)
w + z = 200 ….(ii)
w + y = 175 ….(iii)
M + x + w + y = 185 ….(iv)
P + x + w + z = 210 ….(v)
C + y + w + z = 222 ….(vi)
M + P + C + y + x + z + w = 233 ….(vii)
By (iv) + (v) + (vi) – (vii),
x + y + z + 2w = 384 ….(viii)
by (i) + (ii) + (iii),
x + y + z + 3w = 555 ….(ix)
By (ix) – (viii),
w = 171
From equation (i),
x = 9
From equation (ii),
z = 200 – 171 = 29
From equation (iii),
y = 175 – 171 = 4
M = 185 – 4 – 9 – 171 = 1
P = 210 – 9 – 171 – 29 = 1
C = 222 – 4 – 29 – 171 = 18
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