Hello and welcome to exampundit . So here is a Micromock for IBPS RRB Officer Scale I exam with the new coding-decoding pattern of IBPS PO VI Mains.
REASONING
[Directions 1-5]:
In a certain coding system the following statements are coded as shown below.
Accordingly answer the following questions.
In a certain coding system the following statements are coded as shown below.
Accordingly answer the following questions.
Cow is on super mom =>
&6n *10s $4o
#4t @6x
&6n *10s $4o
#4t @6x
Monday chef only shallow=> &12z
@8g *14x $8z
@8g *14x $8z
Mother custard onset silk=> &12s $10u *8l @14e
Curtain one ink severe maps => $6f @14o #6l &8t *12f
1. “severe only
inhale” may be coded as :
inhale” may be coded as :
1) *12p $18z $5t
2) *12f $8z #12f’
3) %12f $6z #10g
4) @12f $8z #2e
5) &12f $8z #12t
2. What will be the
code for “mandatory” ?
code for “mandatory” ?
1) @4t
2) @12f
3) #12z
4) *18z
5) &18z
3. “@14e” may be the
code for?
code for?
1) Mustard
2) Monkey
3) Children
4) Cold
5) Custard
4.Find the wrong
pair:
pair:
1) Cow- @6x
2) Owl-$6m
3) Iced-*8f
4) Soar-*8s
5) All are correct
5.What will be the
definite code for “ orange mood silk cabin car” ?
definite code for “ orange mood silk cabin car” ?
1) *10l @10p $10f
&4e @6s
&4e @6s
2) @10o @6s *8l
$12f &8e
$12f &8e
3) *8y *10h $12f
&8e &6s
&8e &6s
4) *6l #10o $12g
&8e %6s
&8e %6s
5) *8k @10o #2f
&4e @6h
&4e @6h
English Language
[Directions 6-10]:
Choose the correct form :
Choose the correct form :
6. I should have
liked _____
liked _____
1) To go
2) To have gone
3) To be gone
4) For going
5) To went
7. Rakesh was made ____ the whole serving.
1) To do
2) Do
3) Doing
4) Done
5) To doing
8.Sultan made his
students ____ the whole exercise.
students ____ the whole exercise.
1) To do
2) Do
3) For doing
4) Done
5) To done
9. Of two evils,
choose the ________
choose the ________
1) Least
2) Less
3) Lesser
4) More less
5) Most less
10. The committee has
appended a note to _____ report.
appended a note to _____ report.
1) Its
2) Their
3) His
4) Her
5) His/her
Quantitative Aptitude
[Directions 11-15]:
Find the value of ?
Find the value of ?
11.18/7 +
61/5 + 10/7
– 19/7 +33/5
x 10/3
61/5 + 10/7
– 19/7 +33/5
x 10/3
a) 685/31
b) 682/35
c) 345/76
d) 678/89
e) None
12. 42.09% of 9567.98
÷ 67% of 222.1426 = (?)3
÷ 67% of 222.1426 = (?)3
a) 2
b) 3
c) 1
d) 5
e) None
13.
√32041+√441-√3969+√3364-√196x√961=?
√32041+√441-√3969+√3364-√196x√961=?
a) 239
b) -239
c) 245
d) 245
e) 657
14.78×63÷2+3961×8-√3481×0.006-√1517824=?
a) 32000
b) 32912
c) 34567
d) 45672
e) None
15.65.03÷12.73+986.83÷3+78.0004=?
a) 450
b) 412
c) 390
d) 380
e) None
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Answers:
- Ans-2
- Ans-5
- Ans-5
- Ans-3
- Ans-2
- Ans-1
- Ans-1
- Ans-2
- Ans-2
- Ans-1
- Ans-2
- Ans-2
- Ans-2
- Ans-2
- Ans-2
Solutions:
1-5:
Every code has three parts- a symbol, a number and an
alphabet
alphabet
Each starting letter of the words hav been assigned a
specific symbol as follows
specific symbol as follows
C-@
I-#
O-$
M-&
S-*
The number in the code is the (number of letters in the
uncoded word x2)
uncoded word x2)
Cow= 3×2=6
Monday= 6×2=12 and so on
The Alphabet in the code is the succeeding alphabet of the
last alphabet of the uncoded word
last alphabet of the uncoded word
Cow= last alphabet W hence X in the code
11-15:
11. 18/7 +61/5 +10/7
-19/7 +6
-19/7 +6
=682/35
12. = 42% of 9568 ÷ 67% of 222
= 4018÷148 = 27
or, ?3 = 33 => ? = 3
13. √32041+√441-√3969+√3364-√196x√961
=179+21-63+58-14×31=179+21+58-63-434=-239
14. 78×63÷2+3961×8-√3481×0.006-√1517824
=2457+31688-0.354-1232
=32912.64~32912
15. 65.03÷12.73+986.83÷2+78.0004
=65÷13+987÷3+78
=5+329+78
=412
Regards
Team ExamPundit
This post was last modified on November 27, 2017 8:55 am