Hello and welcome to ExamPundit. Here is a set Data Interpretation Problems.
Study the following graph carefully and answer the questions
given below.
given below.
Percentage growth in population of six states A, B, C, D, E
and F from 2012 to 2013 and 2013 to 2014.
and F from 2012 to 2013 and 2013 to 2014.
1. Population of
state ‘F’ in 2013 was approximately what percent of its population in 2014 ?
state ‘F’ in 2013 was approximately what percent of its population in 2014 ?
(a) 60
(b) 67
(c) 75
(d) 55
(e) None of these
2. If the population
of state ‘B’ in the year 2012 was 5 lakh, what was approximately its population
in the year 2014?
of state ‘B’ in the year 2012 was 5 lakh, what was approximately its population
in the year 2014?
(a) 9.50 lakh
(b) 8 lakh
(c) 10.50 lakh
(d) 14.50 lakh
(e) None of these
3. If the population
of states C and D in 2013 are in the ratio of 2 : 3 respectively and the population
of state ‘C’ in 2012 was 2.5 lakh,
what was the population of state ‘D’ in 2013 ?
of states C and D in 2013 are in the ratio of 2 : 3 respectively and the population
of state ‘C’ in 2012 was 2.5 lakh,
what was the population of state ‘D’ in 2013 ?
(a) 5.25 lakh
(b) 4.75 lakh
(c) 3.50 lakh
(d) 6 lakh
(e) None of these
4. In 2012 the
population of states B and D are equal and the population of state B in 2014 is
4 lakh, what approx was the population
of state ‘D’ in 2014?
population of states B and D are equal and the population of state B in 2014 is
4 lakh, what approx was the population
of state ‘D’ in 2014?
(a) 3 lakh
(b) 3.50 lakh
(c) 6 lakh
(d) 5 lakh
(e) None of these
5. Population of
state ‘E’ in 2012 was what fraction of its population in 2014?
state ‘E’ in 2012 was what fraction of its population in 2014?
(a) 2/3
(b) 4/5
(c) 5/4
(d) 3/2
(e) None of these
Solutions:
1. Let the population of state ‘F’ in 2013 = 100
Then population of state ‘F’ in 2014 = 150 (Since growth is
50%)
50%)
So, Required % = 100/150 × 100 » 67%
2. Population of state ‘B’ in the year 2014 =
5 × 155/100 135/100
»
10.50 lakh
10.50 lakh
3. C12/D12 = 2/3
and C12 = 2.50 Lakhs
and C12 = 2.50 Lakhs
So, C12 = 2.5 x 140/100 =
3.5 Lakhs
3.5 Lakhs
So we get, the population of D in 2013 = 3 x 3.50/2
= 5.25 Lakhs
= 5.25 Lakhs
4. Population of state ‘B’ in 2012
= 4 × 100 × 100/155 × 135= Population
of D in 2012
of D in 2012
Population of state ‘D’ in 2014 = 1×100×100×160×170/100×100×155×135
= 5 lakhs
5. Suppose population of state E in 2012 = 100
Then population of state E in 2013 = 125
*since 25% growth
And population of state E in 2014 = 125 (120/100)
= 150
= 150
*since 20% growth
So, required ratio = 100/150 = 2/3
Regards
Team ExamPundit
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This post was last modified on June 2, 2019 12:12 pm