Hello and welcome to exampundit. Here is a set of Chapterwise Quantitative Aptitude Quiz from Previous Paper for IBPS Clerk 2017 based on Average.
are 45. If the average marks of the passed students are 50 while the average
marks of the failed students is 40. Then find the number of students who passed
the examination. (IBPS Clerk 2015)
of the first 12 students is 14 kg and of the last 12 students is 17 kg. Find
the weight of the thirteenth student. (IBPS SO 2015)
of 20 of them was 22 years and that of another 20 was 24 years. Find the average
age of the remaining girls. (SBI PO Prelim 2015)
cm, 148 cm and 158 cm. What is the average height of all these boys? (SBI JA
& JAA 2016)
mother’s age was 24 when his sister who is 5 years younger to him, was born.
What is the difference between the age of James’ father and mother? (IBPS PO
Pre 2016)
David’s brother is three year older to James. The respective ratio between
present ages of David father and David’s brother is 14:5. What is the present
age of David? (IBPS PO Mains 2016)
was twice old as Rohit 15 years ago. What will be the age of Ronit 6 years
after? (SBI PO Pre 2016)
8:13.Present age of their ages ratio is 5:7.What is the present age of B ? (SBI
PO Mains 2016)
Answers:
- C
- E
- A
- D
- D
- A
- A
- B
Solutions
1.Let P = passed students and failed students = F. So
45 × 100 = 50 × P + 40 × F and P + F = 100. Solve for F
and P, we will get P = 50.
2. Sum of the weight of 25 students
= (25 × 16)kg
Sum of the weight of first 12 students
= (14 × 12)kg = 168 kg
Sum of the weight of last 12 students
= (17 × 12) kg = 204 kg
Weight of the thirteenth student
= (400 – 168 – 204) kg = 28 kg
3. Total age of remaining 40 girls
= (80 × 20 – 20 × 22 – 20 × 24) years
= (1600 – 440 – 480) years
= 680 years
Required average age = 680/40 = 17 years
4. Average height
= 146 + 154 + 164 + 148 + 158/5 = 770/5 = 154 cm
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This post was last modified on July 20, 2019 12:37 pm