H*ello and welcome to ***exampundit**. Here is a set of Puzzle Quiz for SBI PO Prelims 2017.

**Questions 1 to 3:**

Four friends are sitting at the

four sides of a square table at a Café. Eighteen cookies and many sachets of

sugar, all of equal size, are kept at the table. The one opposite Sam has black

coffee with twice as many sachets of sugar as him and three cookies more than

him. Joe has half as many sachets of sugar but twice as many cookies as the one

opposite him. Sam has the same number of cookies as one of his friends. Raman

has more sugar in his coffee than Arun and also adds milk to it. No one uses a

sachet partially or has more than four sachets.

four sides of a square table at a Café. Eighteen cookies and many sachets of

sugar, all of equal size, are kept at the table. The one opposite Sam has black

coffee with twice as many sachets of sugar as him and three cookies more than

him. Joe has half as many sachets of sugar but twice as many cookies as the one

opposite him. Sam has the same number of cookies as one of his friends. Raman

has more sugar in his coffee than Arun and also adds milk to it. No one uses a

sachet partially or has more than four sachets.

1. How does Arun have his coffee?

1) Black, with 1 sachet of sugar

2) With milk and 3 sachets of

sugar

sugar

3) Black, with 2 sachets of sugar

4) Cannot be determined

2. Which of the following is

true?

true?

1) The one opposite Arun uses 2

sachets of sugar less than him.

sachets of sugar less than him.

2) The one opposite Raman eats 3

cookies more than him.

cookies more than him.

3) The one opposite Joe uses 1

sachet of sugar more than him.

sachet of sugar more than him.

4) The one opposite Sam eats 5

cookies.

cookies.

3. Which of the following is

false?

false?

1) Arun sits next to someone who

uses same number of sachets as him.

uses same number of sachets as him.

2) Joe sits next to someone who

eats the same number of cookies as him.

eats the same number of cookies as him.

3) Raman sits next to someone who

uses same number of sachets as him.

uses same number of sachets as him.

4) Sam sits next to someone who

eats the same number of cookies as him.

eats the same number of cookies as him.

**Questions 4 to 7:**

Eight members of a trekking club

– A, B, C, D, E, F, G and H – plan to go trekking this weekend. Two

simultaneous treks – Trek I and Trek II – are planned, each of which will have

exactly 4 participants. A, C and G are doctors. A, B, E and H have prior

trekking experience. It is decided that each group should have at least 1

doctor and 2 members with prior experience. Also B and C must be in different

groups.

– A, B, C, D, E, F, G and H – plan to go trekking this weekend. Two

simultaneous treks – Trek I and Trek II – are planned, each of which will have

exactly 4 participants. A, C and G are doctors. A, B, E and H have prior

trekking experience. It is decided that each group should have at least 1

doctor and 2 members with prior experience. Also B and C must be in different

groups.

4. If D and F insist in going on

Trek II, which of the following must also go on Trek II?

Trek II, which of the following must also go on Trek II?

1) G

2) E

3) B

4) H

5. If F and C go on Trek II, then

in how many ways can the group for Trek I be formed?

in how many ways can the group for Trek I be formed?

1) 1 way

2) 2 ways

3) 3 ways

4) No such group possible

6. If A is the only doctor in his

group, then which of the following is necessarily true?

group, then which of the following is necessarily true?

1) B and G go on the same trek.

2) E and G go on different treks.

3) D and F go on the same trek.

4) D and F go on different treks.

7. If A and B go on different

treks, which of the following could be true?

treks, which of the following could be true?

1) A and G go on the same trek.

2) D and F go on the same trek.

3) E and H go on the same trek.

4) F and H go on the same trek.

Answers & Solutions:

Question 1 to 3:

- 3
- 2
- 3

We first make an elementary

table:

table:

Number of cookies with Sam must

be m or 2m. But if it is 2m then we get 7m + 3 = 18 which is not possible. So,

Sam has m cookies with m = 3 (5m + 3 = 18). Also, Raman adds milk so he cannot

be opposite to Sam. And since Raman has more sugar than Arun, 2y > 2x. The

only possibility then is x = 1, 2x = y = 2, 2y = 4. We thus get the complete

table:

be m or 2m. But if it is 2m then we get 7m + 3 = 18 which is not possible. So,

Sam has m cookies with m = 3 (5m + 3 = 18). Also, Raman adds milk so he cannot

be opposite to Sam. And since Raman has more sugar than Arun, 2y > 2x. The

only possibility then is x = 1, 2x = y = 2, 2y = 4. We thus get the complete

table:

4. Neither D nor F have prior experience,

and neither is a doctor. So the only way to fulfil the given conditions is if

A, who also has prior experience, goes as the doctor, while the 4th member also

has prior experience. Thus the other doctors, C and G, must go on Trek I, and B

must be on Trek II. Hence (3).

and neither is a doctor. So the only way to fulfil the given conditions is if

A, who also has prior experience, goes as the doctor, while the 4th member also

has prior experience. Thus the other doctors, C and G, must go on Trek I, and B

must be on Trek II. Hence (3).

5. If F and C go on Trek II, B

must go on Trek I. Trek II requires the remaining 2 people to have prior

experience and hence D and G also must go on Trek I. Now, any one of the three

remaining people with prior experience (A, E and H) can be sent on Trek I and

the other two on Trek II. Hence 3 ways. Hence (3).

must go on Trek I. Trek II requires the remaining 2 people to have prior

experience and hence D and G also must go on Trek I. Now, any one of the three

remaining people with prior experience (A, E and H) can be sent on Trek I and

the other two on Trek II. Hence 3 ways. Hence (3).

6. If A is the only doctor in his

group, C and G must be in the other group. Thus B must be in the first group. Also,

the other two with C and G must be having prior experience. Thus they must be E

and H, while D and F must go with A and B. Hence (3).

group, C and G must be in the other group. Thus B must be in the first group. Also,

the other two with C and G must be having prior experience. Thus they must be E

and H, while D and F must go with A and B. Hence (3).

7. Since both A and C cannot go

with B, they must be together. Hence the remaining doctor, G, must go with B.

Also, each group has only one experienced person so far, and hence E and H must

go to different groups. Similarly the fourth spot in each group must be taken

by D and F, one to each group. Hence the options (1), (2) and (3) are all

impossible, but option (4) could take place (for example Trek I – A, C, D, E

and Trek II – B, F, G, H is a possible combination). Hence,(4).

with B, they must be together. Hence the remaining doctor, G, must go with B.

Also, each group has only one experienced person so far, and hence E and H must

go to different groups. Similarly the fourth spot in each group must be taken

by D and F, one to each group. Hence the options (1), (2) and (3) are all

impossible, but option (4) could take place (for example Trek I – A, C, D, E

and Trek II – B, F, G, H is a possible combination). Hence,(4).

####
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