SBI PO Mains 2017: New Coding Decoding Problems in Reasoning – Set 6

Hello and welcome to exampundit. Here is a set of New Pattern Coding Decoding for SBI PO Mains 2017.

Given below is a set of sentences along
with their codes in a specific machine language.
Watched pot never boils  –
4&g 13\$u  11#w 25\$v
Beggars cannot choose –  24%w 24%h
25&v
Familiarity breeds contempt –  25%v
24*w  21+b
Counsel is no command –  24&o
[email protected] 24&g  [email protected]
According to the above coding pattern,
1. What will be the code for “ bemuzzle
fuzzed” ?
a) 21%g
25*h
b) 21*g
25%h
c) 20%r
16&t
d) Either a or b
e) None
2. ”ace” will be coded as?
a) 20%t
b) 3&t
c) 26#h
d) 26*t
e) None
3. ”muzzling as crazy” will be coded as?
a) 14*j
24\$b  [email protected]
b) [email protected]
14&b  20&t
c) 3&t
17+y  25&r
d) Either b or c
e) None
4. What will be the code for “ scuzzy
quick” ?
a) 10&t
18&e
b) 10&n 17%r
c) 8%b
10\$n
d) Either b or c
e) None
5. ”17\$b” will be the code for?
a) Jamie
b) Jammy
c) Yummy
d) Tommy

e) Fanny

1. Ans-a
2. Ans-c
3. Ans-a
4. Ans-c
5. Ans-b

Solution-
Every code consists of three parts- a
number (either 1 or 2 digit) , a symbol and a letter of English alphabet.
The number in the code is the reverse
numeric value of the first letter of the word
For example 4=w, 11=p, 13=n.
The symbol is coded with respect to the
number of digits in the word.
By comparing the common terms of codes and
eliminating we get the following :
3=#
5=\$
6=%
7=&
8=*
11=+
The letter in the code is the alphabet two
places to left of the last letter of the word.
For example in the word never, r is the
last letter hence the last part of the code will be r+2=u
Hence the words and their codes are:
Watched
pot       never      boils
4&g           11#w     13\$u
25\$v
Beggars     cannot     choose
25&v          24%w       24%h
Familiarity     breeds   contempt
21+b             25%v         24*w
Counsel      is        no
command