Hello and welcome to exampundit. Here is a set of Reasoning Quiz on Coded Inequalities.
Directions (Qs.1-5): In the following questions, the symbols @, #, $, * and % are used as illustrated below:
‘P @ Q’ means ‘P is not smaller than Q’.
‘P # Q’ means ‘P is neither greater than nor equal to Q’.
‘P $ Q’ means ‘P is neither smaller than nor greater than Q’.
‘P * Q’ means ‘P is not greater than Q’.
‘P % Q’ means ‘P is neither smaller than nor equal to Q’.
Now, in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true? Give answer
(a) if only Conclusion I is true.
(b) if only Conclusion II is true.
(c) if either Conclusion I or II is true.
(d) if neither Conclusion I nor II is true.
(e) if both Conclusions I and II are true.
- Statements:
M $ K, D * K, R # K
Conclusions:
- D $ M
- M % D
Show Answer
Option: C
Explanation:
M = K .…. (i);
D ≤ K ….. (ii);
R < K ..… (iii)
From (i) and (ii), we get
M = K ≥ D –> M ≥ D
Hence, either M > D (conclusion II) or M = D (conclusion I) is true
- Statements:
F * M, M % R, E @ F
Conclusions:
- M % E
- R @ E
Show Answer
Option: D
Explanation:
F ≤ M… (i); M > R… (ii); E ≥ F… (iii)
From (i) and (iii), no specific relation can be obtained between M and E. Similarly, no specific relation can be obtained between R and E.
- Statements:
H $ K, T # H, W * T
Conclusions:
- K % W
- T # K
Show Answer
Option: E
Explanation:
H = K… (i); T < H…(ii),
W ≤ T …(iii)
From (i), (ii) and (iii), we get
K = H > T ≥ W –> K > W (conclusion I) and T < K (conclusion II).
- Statements:
N % A, A # L, F $ N
Conclusions:
- L % F
- F % A
Show Answer
Option: B
Explanation:
N > A… (i), A < L… (ii), F = N…(iii)
From (i) and (iii), we get
F = N > A–> F > A (conclusion II). But no specific relation can be obtained between L and F. Hence, conclusion I is not necessarily true.
- Statements:
B * D, D $ M, F % M
Conclusions:
- B # M
- F % B
Show Answer
Option: B
Explanation:
B ≤ D…(i); D = M…(ii); F > M …(iii)
From (i), (ii) and (iii), we get
F > M = D ≥ B –> B < M and F > B (conclusion II).
Since, B < M, therefore, conclusion I is not necessarily true.
Directions (Qs. 6-11): In the following questions the symbols +, ×, ?, @ and $ are used with the following meanings:
P + Q means P is neither smaller nor greater than Q.
P × Q means P is neither equal to nor smaller than Q.
P ? Q means P is neither greater than nor equal to Q.
P @ Q means P is either greater than or equal to Q.
P $ Q means P is not equal to Q.
Now, in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/are definitely true. Give answer
(a) if only conclusion I is true;
(b) if only conclusion II is true;
(c) if either I or II is true:
(d) if neither I nor II is true; and
(e) if both I and II are true.
- Statements:
P $ Q, Q × R, P + R
Conclusions:
- Q × P
- P ? Q
Show Answer
Option: E
Explanation:
P ≠ Q …(i), Q > R … (ii), P = R …(iii)
From (ii) and (iii), we get Q > R = P –> Q > P. Hence, both I and II are true.
- Statements:
A + B, B $ C, C ? A
Conclusions:
- C $ A
- B + C
Show Answer
Option: A
Explanation:
A = B … (i), B ≠ C … (ii), C < A … (iii)
From (iii), conclusion I is true. II contradicts statement (ii), hence, it is not true.
- Statements:
Y @ Z, Z × Q, Q $ P
Conclusions:
- Y ? Q
- Y ? P
Show Answer
Option: D
Explanation:
Y ≥ Z …(i), Z > Q … (ii), Q ≠ P …(iii)
From (i) and (ii), we get Y > Z > Q –> Y > Q … (A)
Hence, I is not true. From (iii), two possible relationships between P and Q are;
Case I: When P > Q
Now, using (A), we get Y > Q < P –> no conclusion.
Case II: When Q > P using (A), we get Y > Q > P –> Y > P. Hence, II is not true.
- Statements:
E × F, F @ L, L+ N
Conclusions:
- N + F
- E × L
Show Answer
Option: B
Explanation:
E > F …. (i), F ≥ L … (ii), L = N …(iii)
From (ii) and (iii), we get F ≥ L= N –> F ≥ N or N′ F.
Hence, I may be true but not necessarily so.
From (i) and (ii), we get E > F ≥ L –> E > L
Hence, II is true.
- Statements:
H @ J. J ? K, K × M
Conclusions:
- H @ M
- M × J
Show Answer
Option: D
Explanation:
H ≥ J … (i), J < K … (ii), K > M … (iii)
From (ii) and (iii), we get J < K > M fi no relationship between J and M can be established. Hence, II can’t be established. Again, combining all we can’t conclude the relationship between H and M. Hence, I is not true.
- Statements:
M @ T, T + V, V ? E
Conclusions:
- V + M
- V ? M
Show Answer
Option: C
Explanation:
M ≥ T … (i), T = V …. (ii), V < E …(iii)
From (i) and (ii), we get
M ≥ T = V –-> M ≥ V –> either V = M or V < M is true.
Regards
Team EP
