Hello and welcome to exampundit. Here is a set of Missing Data DI for Upcoming IBPS PO, RRB & Clerk Exams
A professor keeps data on students tabulated by performance and sex of the student. The data is kept on a computer disk, but unfortunately some of it is lost because of a virus. Only the following could be recovered:
Panic buttons were pressed but to no avail. An expert committee was formed, which decided that the following facts were self evident:
1. Half the students were either excellent or good.
2. 40% of the students were females.
3. One third of the male students were average.
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1: How many students were both female and excellent?
(a) 0
(b) 8
(c) 16
(d) 32
2: How many students are both male and good?
(a) 10
(b) 16
(c) 22
(d) 48
3: Among average students, what is the ratio of male to female?
(a) 1 : 2
(b) 2 : 1
(c) 3 : 2
(d) 2 : 3
4: What proportion of female students are good?
(a) 0
(b) 0.25
(c) 0.5
(d) 1.0
5: What proportion of good students are male?
(a) 0
(b) 0.73
(c) 0.4
(d) 1.0
Explanations:
1. From the table it is given that the number of females is 32 and this number is 40% of the students. This means that the total number of students is 80 and the number of boys
2. Now in the question we are given that half the students were excellent Also, it is given that one third of the male students were average. So the number of
3. (Number of average students) = (number of good students + number of excellent for the number of excellent students = 40 – 30 = 10.
4. Total good students = 30
5. Therefore the number of excellent students = 40 – 30 = 10
6. Also in the question it is mentioned that 1/3rd of male students were average, therefore total number of boys students that were good = (48 – 16 – 10) = 22.
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Now from this information our graph will change into the following graph:
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